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3 years ago

W=90 kg×4n/kgPlease halp me i need it

1 answer:

5 0

I'm guessing that this is a problem to find the weight of a 90kg mass on a planet where the acceleration of gravity is 4 m/s^2. (Much less gravity than Earth, a little more than Mars.)

Just do the multiplication, and you get

360 Newtons.

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The minimum resultant of two forces of 20N and 5N is: a) 10N b) 5N c) 20N d) 25N

notka56 [123]

Answer:

if it's combined forces then it would be 25N if it was an unbalanced force then it would be 15N

8 0

4 years ago

Wall-E the robot is resting when he randomly explodes into two pieces that fly off in opposite directions. His head has a mass o

Brut [27]

Answer:

The body flies off to the left at 9.1 m/s

Explanation:

Law Of Conservation Of Linear Momentum

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

$P=m_1v_1+m_2v_2+...+m_nv_n$

If a collision occurs and the velocities change to v', the final momentum is:

$P'=m_1v'_1+m_2v'_2+...+m_nv'_n$

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

$m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\qquad\qquad[1]$

Wall-E robot is initially at rest, its two parts together. His head has a mass of m1=0.75 kg and his body has a mass of m2=6.2 kg. Both parts have initial speeds of zero v1=v2=0.

After the explosion, his head flies off to the right at v1'=75 m/s. We are required to find the speed of his body v2'. Solving [1] for v2':

$\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}$

Substituting values:

$\displaystyle v'_2=\frac{0.75*0+6.2*0-0.75*75}{6.2}$

$\displaystyle v'_2=-9.1 \ m/s$

The body flies off to the left at 9.1 m/s

3 0

3 years ago

A swimming pool is 4.0 m in depth; a swimmer at this depth feels discomfort in the ear. Calculate the net force on a 0.50-cm-dia

Mashcka [7]

The net force on a 0.50-cm-diameter eardrum is mathematically given as

F= 0.76969 N

<h3>What is the net force on a 0.50-cm-diameter eardrum?</h3>

Generally, the equation for Pressure is mathematically given as

P = ρgh

Therefore

P= 1000*9.8*4

P= 39200 Pa

Where

A= pi*(0.005/2)^2

Generally, the equation for Net force is mathematically given as

F = PA

F= 39200 *( pi*(0.005/2)^2)

F= 0.76969 N

In conclusion, The net force is

F= 0.76969 N

Read more about Pressure

#SPJ1

5 0

2 years ago

1. Describe the vibration caused by primary waves.

mrs_skeptik [129]

Energy released during an earthquake travels in the form of waves around the Earth. Two types of seismic wave exist, P- and S-waves. They are different in the way that they travel through the Earth. ... They are transverse waves which mean the vibrations are at right angles to the direction of travel.

5 0

4 years ago

When you drop a 0.43 kg apple, Earth ex erts a force on it that accelerates it at 9.8m / (s ^ 2) toward the earth's surface. Acc

Sever21 [200]

Answer:

The answer to the question is highlighted in the box

8 0

1 year ago

W=90 kg×4n/kgPlease halp me i need it ​

W=90 kg×4n/kgPlease halp me i need it