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3 years ago

Which of the following best describes the domains of unmagnetized iron?

1 answer:

8 0

Magnetic domain is defined as a group of atoms with magnetic fields.

A piece of iron can only become a magnet when the magnetic domain aligns.

Since we have an unmagnetized piece of iron, this means that its domain is not aligned. However, this does not mean that the domain does not exist.

Based on the above, the best choice would be:
There arr domains, but domains are oriented randomly.

Hope this helps :)

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it is defined as the intersection of two lines;describes a position in space and has no length, width or height

Ksivusya [100]

Answer:

Could you explain more?

Explanation:

5 0

2 years ago

Question 8

Marrrta [24]

Answer:

It has a mass of 40 kg.

Explanation:

Because Force = mass x Acceleration or F = m a, we could say that the mass is force/acceleration which in your case is 2,400/60 which equals 40 kg.

3 0

2 years ago

A wheel decelerates from 13.5 rad s−1 to 6.0 rad s−1 in 7 s. Calculate the angular displacement

Igoryamba

Answer:

Angular displacement=68.25 rad

Explanation:

Circular Motion

If the angular speed varies from ωo to ωf in a time t, then the angular acceleration is given by:

$\displaystyle \alpha=\frac{\omega_f-\omega_o}{t}$

The angular displacement is given by:

$\displaystyle \theta=\omega_o.t+\frac{\alpha.t^2}{2}$

The wheel decelerates from ωo=13.5 rad/s to ωf=6 rad/s in t=7 s, thus:

$\displaystyle \alpha=\frac{6-13.5}{7}$

$\displaystyle \alpha=\frac{-7.5}{7}$

$\displaystyle \alpha=-1.071 \ rad/s^2$

Thus, the angular displacement is:

$\displaystyle \theta=13.5*7+\frac{-1.071*7^2}{2}$

$\displaystyle \theta=94.5-26.25$

$\boxed{\displaystyle \theta=68.25\ rad}$

Angular displacement=68.25 rad

3 0

3 years ago

Old-fashioned pendulum clocks are powered by masses that need to be wound back to the top of the clock about once a week to coun

Andreyy89

Answer:

Energy, E = 178.36 J

Explanation:

It is given that,

Mass 1, $m_1=4\ kg$

Mass 2, $m_2=4\ kg$

Mass 3, $m_3=6\ kg$

Height from which they are dropped, h = 1.3 m

Let m is the energy used by the clock in a week. The energy is equal to the gravitational potential energy. It is given by :

$E=(m_1+m_2+m_3)gh$

$E=(4+4+6)\times 9.8\times 1.3$

E = 178.36 J

So, the energy used by the clock in a week is 178.36 Joules. Hence, this is the required solution.

6 0

3 years ago

Rosa uses the formula (vi¡cosθ)tΔ to do a calculation. Which value is Rosa most likely trying to find?

andriy [413]

To break this problem down, let's start with what we know. The equation given finds one component of the velocity and multiplies it by the change in time. This will not find the acceleration that the first two answers say it will, meaning that the answer isn't A or B.

That leaves us with the final two answers, C and D. If the projectile was launched horizontally and we were trying to find the horizontal displacement, we wouldn't need to use cosθ to find the horizontal velocity, meaning that our answer is most likely C) the horizontal displacement of a projectile launched at an angle!

4 0

3 years ago