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Vera_Pavlovna [14]
3 years ago
6

Which of the following experimental observations proved that the idea of matter and mass being evenly distributed in an atom was

flawed?
A. Less than 1% of the alpha particles went un-deflected through the gold foil.
B. Less than 1% of the alpha particles were deflected by angles greater than 90°.
C. The beam from the negative electrode was deflected by electrically charged rods.
D. The beam from the negative electrode cast a shadow on the positive electrode.
Chemistry
2 answers:
Ksenya-84 [330]3 years ago
7 0

A. Less than 1% of the alpha particles went un-deflected through the gold foil.

nasty-shy [4]3 years ago
6 0

Answer:

B. Less than 1% of the alpha particles were deflected by angles greater than 90°.

Explanation:

In Rutherford’s gold foil experiment most of the alpha particles pass undeflected which proved that most of the atom is empty. Less than 1% of the alpha particles were deflected by angles greater than 90°. This proved that the entire mass of the atom is confined to a small space which is highly dense.

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The densities of gases a, b, and c at stp are 1.25 g/l, 2.86 g/l and 0.714 g/l, respectively. calculate the molar mass of each s
kicyunya [14]
The  molar  mass  of    a, b and  c at  STP is calculated  as  below

At  STP  T  is always=   273 Kelvin and ,P= 1.0 atm 

by  use of  ideal  gas  equation  that  is  PV =nRT
n(number   of moles) = mass/molar mass  therefore  replace   n  in  the  ideal   gas  equation

that  is Pv = (mass/molar mass)RT
multiply  both side  by molar  mass  and  then  divide  by  Pv  to  make  molar mass the  subject of the  formula

that is  molar  mass =  (mass x RT)/ PV

 density is always = mass/volume

therefore  by  replacing  mass/volume  in   the equation  by  density the equation
molar  mass=( density  xRT)/P  where R  =  0.082 L.atm/mol.K

the  molar mass  for  a
= (1.25 g/l  x0.082 L.atm/mol.k  x273k)/1.0atm = 28g/mol

the molar  mass of b
=(2.86g/l  x0.082L.atm/mol.k   x273  k) /1.0  atm  = 64  g/mol

the molar  mass of c

=0.714g/l  x0.082  L.atm/mol.K  x273 K) 1.0atm= 16 g/mol

therefore  the 
   gas  a  is  nitrogen N2   since 14 x2= 28 g/mol
   gas b =SO2  since  32 +(16x2)= 64g/mol
  gas c =   methaneCH4  since  12+(1x4) = 16 g/mol


8 0
3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
What is photosynthesis?????​
PilotLPTM [1.2K]

Photosynthesis is the process by which plants use sunlight, water, and carbon dioxide to create oxygen and energy in the form of sugar.

3 0
3 years ago
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What diffuses more quickly: tetracarbon decahydride (C4H10) or iodine (12)? By how much?
ValentinkaMS [17]

Answer: Butane will effuse more quickly because it has a smaller molar mass

Explanation:

Molar mass of C4H10 = 58.123 g/mole

Molar mass of I2 = 253.808 g/mole

5 0
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If some salt were accidently spilled as it was transferred from the balance to the cup would your calculated enthalpy of solutio
morpeh [17]

Answer:

It would be to low

Explanation:

7 0
3 years ago
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