5.16 meters!!!!!!!!!!!!!!!!!!!!
As we know that KE and PE is same at a given position
so we will have as a function of position given as

also the PE is given as function of position as

now it is given that
KE = PE
now we will have




so the position is 0.707 times of amplitude when KE and PE will be same
Part b)
KE of SHO at x = A/3
we can use the formula

now to find the fraction of kinetic energy



now since total energy is sum of KE and PE
so fraction of PE at the same position will be


Answer:

Explanation:
Given data:
PERIOD OF MOTION IS T = 25.5 days
orbital speeds = 220 km/s
we know that
acceleration due to centripetal force is
Gravitational force
we know that

solving for





we know that
f =ma

solving for m



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sorry if this is wrong, i hope i helped