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rusak2 [61]
3 years ago
12

A racecar drives at a constant speed down a straight track. The car is in _?_

Physics
1 answer:
vagabundo [1.1K]3 years ago
7 0

Answer:

the answer is

the car is in motion

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Suatu sistem gas berada didalam ruang yang fleksibel. Pada awalnya gas berada pada kondisi P1 = 1,5 × 10 pangkat 5 N/m2, T1 = 27
enot [183]

Answer:

16.00L

Explanation:

First you calculate the number of moles in the system:

PV=nRT\\\\n=\frac{PV}{RT}\\\\n=\frac{(1.5*10^5N/m^2)(12L)}{(0.082L.atm/mol.K)(300.15K)}=73134.16\ mol

To find the new volume of the system you use the following formula for an isobaric procedure:

T_2-T_1=\frac{P}{nR}(V_2-V_1)\\\\V_2=\frac{nR}{P}(T_2-T_1)+V_1\\\\V_2=\frac{(73134.16\ mol)(0.082L.atm/mol.K)}{1.5*10^5N/m^2}(400.15-300.15)K+12L\\\\V_2=16.00L

hence, the new volume is 16.00L

6 0
4 years ago
What explains the dramatically different magnitudes of accelerations that result when a mosquito collides head on with a moving
Evgen [1.6K]

Answer:

Mass of the vehicle and small bug.

Explanation:

  • By Newton's third law, force on bug and vehicle will be same when they collide with each other irrespective of their masses.
  • But according to Newton's second law, force is mass times acceleration. Since the force on each mass is same, the smaller mass will accelerate more and the heavier mass will accelerate less for the same force.
  • Therefore the acceleration of bug will be very greater than vehicle as the mass of the bug is very small as compared to vehicle.

Learn more about Newton's law.

brainly.com/question/974124

#SPJ10

7 0
3 years ago
A 2 kilogram mass is lifted 4 meters above the ground what is the change it gravitational energy
lianna [129]

Answer:

78.4 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its location in the gravitational field.

The change in gravitational potential energy of an object is given by:

\Delta U=mg\Delta h

where:

m is the mass of the object

g=9.8 m/s^2 is the acceleration due to gravity

\Delta h is the change in height of the object

For the mass in  this problem, we have:

m = 2 kg is the mass

\Delta h = 4 m is the change in height

So, its change in gravitational energy is:

\Delta U=(2)(9.8)(4)=78.4 J

6 0
3 years ago
Whats the life cycle of a star
salantis [7]

Answer:

huge cloud of gas and dust

6 0
2 years ago
You have a string with a mass of 0.0127 kg. You stretch the string with a force of 9.33 N, giving it a length of 1.93 m. Then, y
melomori [17]

Answer:

wavelength = 0.968 m

frequency = 39.02 Hz

Explanation:

given data

mass = 0.0127 kg

force = 9.33 N

length = 1.93 m

to find out

wavelength and Frequency

solution

we know here linear density that is

linear density = \frac{mass}{length}   .........1

linear density = \frac{0.0127}{1.93}

linear density = 6.5803 × 10^{-3} kg/m

so

wavelength will be here

wavelength = \frac{2L}{n}   ..............2

here n = 4 for forth harmonic

wavelength = \frac{2*1.93}{4}

wavelength = 0.968 m

and

frequency will be for 4th normal mode of vibration is

frequency = \frac{4}{2L} \sqrt{\frac{tension}{linear\ density} }    ..........3

frequency = \frac{4}{2*1.93} \sqrt{\frac{9.33}{6.5803*10^{-3}} }

frequency = 1.036269 × 37.654594

frequency = 39.02 Hz

5 0
3 years ago
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