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3 years ago

Describe the physical and chemical changes that take place during digestion

1 answer:

3 0

Physical: food turns into our feces
Chemical: water turns into urine, food digest,
(honestly I think those are the answers)

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I typed a question. It said give points. I selected. Someone answered notification came. But where do I see they persons answer?

Ksivusya [100]

Answer:

212.304 grams

Explanation:

similar to your other question, use the same formula

q=mCpΔT

23617=m(4.182)(46.6-20)

23617=111.2412m

m=212.304g

6 0

2 years ago

an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem

OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

$P\cdot V = n\cdot R\cdot T$ ,

$\displaystyle V = \frac{n\cdot R\cdot T}{P}$ .

where

$P$ is the pressure of the gas,
$V$ is the volume of the gas,
$n$ is the number of moles of particles in this gas,
$R$ is the ideal gas constant, and
$T$ is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of $R$ will be $8.314$ if $P$ , $V$ , and $T$ are in SI units. Convert these values to SI units:

$P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa$ ;
$V$ shall be in cubic meters, $\rm m^{3}$ ;
$T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K$ .

Apply the ideal gas law:

$\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}$ .

4 0

3 years ago

Use the following chemical equation to answer the question. 4K(s) + O2(g) → 2 K2O(s). If a staff member at a laboratory has 12.0

Allushta [10]

Answer:14.5 grams of K2O

Explanation:

4 0

3 years ago

How would you prepare 2.5 L of a 0.800M solution of KNO3?

statuscvo [17]

First find the mass of solute:

Molar mass KNO₃ = 101.1032 g/mol

mass = Molarity * molar mass * volume

mass = 0.800 * 101.1032 * 2.5

mass = 202.2064 g of KNO₃

To prepare 2.5 L (0800 M) of KNO3 solution, must weigh 202.2064 g of salt, dissolve in a Beker, transfer with the help of a funnel of transfer to a volumetric flask, complete with water up to the mark, capping the balloon and finally shake the solution to mix.

hope this helps!

7 0

3 years ago

In June there are fewer hours of daylight and less direct sunlight in the

Dafna11 [192]

In June there are fewer hours of daylight and less direct sunlight in the Southern Hemisphere.

Your answer is Southern Hemisphere.

5 0

3 years ago