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3 years ago

Two internal factors that are important in advancing the cell cycle are

Physics

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Answer:

Kineses and Cyclin

Explanation:

Kineses and Cyclin are the two important internal factors in the advancing of cell cycle.

In response to a stimuli, the nondirectional motion of an organism or cell depends on the strength of the stimulus or the movement without an apparent physical cause is called Kineses.

Any of a variety of cell division-related proteins that are believed to activate some mitosis processes is called Cyclin.

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Which statement is always false for athletes participating in team sports?

tatyana61 [14]

Which statement is always false for athletes participating in team sports?

Answer: Out of all the options shown above the one that best represents the statement that is alway false for athletes participating in team sports is answer choice C) Conflict resolution is a sign of poor sportsmanship. All the other choices are true when it comes to team sports.

I hope it helps, Regards.

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3 years ago

A force can exist between two charged particles or objects even if they're as small as subatomic particles. Between which of the

ASHA 777 [7]

If both particles have the SAME electrical charge, then they repel.
If they have DIFFERENT electrical charge, then they attract.

Protons have + charge .
Electrons have - charge .

So two protons (A) or two electrons (D) push apart.

One proton and one electron (C) pull together.

3 0

3 years ago

Read 2 more answers

Consider a balloon of mass 0.030kg being inflated with a gas of density 0.54kg/m. What will be the volume of the balloon when it

Nonamiya [84]

the weight of the balloon is .030 * 10 = 0.3 N

the weight of the gas of volume v is 0.54*10 N

The lifting force of a volume of v m³ of displaced air is 1.29v N

so, we need

1.29*10*v = 0.3 + 0.54*10*v

1.29v = 0.03+0.54v

7 0

1 year ago

Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa

lyudmila [28]

Answer:

No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field $\vec{E}$ is related to the gradient of the electric potential V with :

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})$

This means that for constant electric potential the electric field must be zero:

$V(\vec{r}) = k$

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k$

$\vec{E} (\vec{r}) = - (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k$

$\vec{E} (\vec{r}) = - (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})$

$\vec{E} (\vec{r}) = - (0,0,0)$

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

$V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4$

give an electric field of zero at point (0,0,0)

8 0

3 years ago

A spherical tank with radius 4 m is half full of a liquid that has a density of 900 kg/m3. The tank has a 1 m spout at the top.

kompoz [17]

The answer & explanation for this question is given in the attachment below.

7 0

3 years ago