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3 years ago

Two internal factors that are important in advancing the cell cycle are

Physics

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Answer:

Kineses and Cyclin

Explanation:

Kineses and Cyclin are the two important internal factors in the advancing of cell cycle.

In response to a stimuli, the nondirectional motion of an organism or cell depends on the strength of the stimulus or the movement without an apparent physical cause is called Kineses.

Any of a variety of cell division-related proteins that are believed to activate some mitosis processes is called Cyclin.

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An object in a certain direction with an acceleration in the perpendicular direction

geniusboy [140]

Answer:

An object moving in certain direction with an acceleration in the perpendicular direction. The above condition is possible . Example of such situation in life would be when stone tied to a string whirling in a circular path

Hope this helps and pls mark as BRAINLIEST :)

3 0

3 years ago

Is this a testable question?

faltersainse [42]

This is a non testable question because it cannot be answered by doing an experiment. But it could be modified for example Dogs are more obedient then cats.

8 0

3 years ago

Read 2 more answers

Please help me :Find the resultant of two forces of 1.5N and 2.0N at 90 degrees to each other, with the 1.5N force acting vertic

Roman55 [17]

Answer:

resultant force = (f1²+f2²)½

=(1.5²+2²)½

=(2.25+4)½

=(6.25)½

=2.5

Explanation:

okay this question seems easy. now if the 1.5 is vertically upwards so is that 2 is horizontally downwards hence as u say its 90 degrees thn it forms a right angled triangle.

4 0

3 years ago

Positive Charge is distributed along the entire x axis with a uniform density 12 nC/m. A proton is placed at a position of 1.00

lions [1.4K]

Answer:

b. $\Delta KE = 390 eV$

Explanation:

As we know that the electric field due to infinite line charge is given as

$E =\frac{\lambda}{2\pi \epsilon_0 r}$

here we can find potential difference between two points using the relation

$\Delta V = \int E.dr$

now we have

$\Delta V = \int(\frac{\lambda}{2\pi \epsilon_0 r}).dr$

now we have

$\Delta V = \frac{\lambda}{2\pi \epsilon_0}ln(\frac{r_2}{r_1})$

now plug in all values in it

$\Delta V = \frac{12\times 10^{-9}}{2\pi \epsilon_0}ln(\frac{1+5}{1})$

$\Delta V = 216ln6 = 387 V$

now we know by energy conservation

$\Delta KE = q\Delta V$

$\Delta KE = (e)(387V) = 387 eV$

3 0

3 years ago

A car is on a circular off ramp of an interstate and is traveling at exactly 25 mph around the curve. Does the car have velocity

netineya [11]

Answer:

The car has velocity and acceleration but is not decelerating

Explanation:

Since the car is traveling at 25 mph around the curve, it has a tangential velocity. This tangential velocity is constantly changing in direction (so the car could adapt to the curve and not moving forward in a straight line), there should be a centripetal acceleration in play here. This acceleration does not slow down the car so it's not decelerating.

6 0

3 years ago