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arsen [322]
3 years ago
13

A rock held at a height of 3 meters what a mass of 2kg has what energy

Physics
1 answer:
monitta3 years ago
5 0
You are looking to find gravitational energy, the formula for that is (height)(weight)(acceleration due to gravity). In your case I️t will be (3)(2)(9.8)= 58.8 Joules
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A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s
saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

F= \frac{mv^2}2

La energía gravitacional por,

F=\frac{GM_cm}{d}

Where m is the mass, v is the velocity, G the gravitational constant M_e the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

E= \frac{mv^2}2+\frac{GM_em}{d}

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2

The case of the comet is a closed orbit, so,

E<0

\frac{mv^2}2+\frac{GM_em}{d}

For parabolic orbit

E=0

\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2

For the sun and the earth

\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}

v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r

where R \approx 1AU

q^2d  For elliptical orbit

8 0
3 years ago
Which of the following is the best paraphrasing of the Heisenberg uncertainty principle?
nadezda [96]
<h2>Answer: The more precisely you know the position of a particle, the less well you can know the momentum of the particle </h2>

The Heisenberg uncertainty principle was enunciated in 1927. It postulates that the fact that each particle has a wave associated with it, imposes restrictions on the ability to determine <u>its position and speed at the same time.  </u>

In other words:  

<em>It is impossible to measure simultaneously (according to quantum physics), and with absolute precision, the value of the position and the momentum (linear momentum) of a particle.</em>  

<h2>So, the greater certainty is seeked in determining the position of a particle, the less is known its linear momentum and, therefore, its mass and velocity.  </h2><h2 />

In fact, even with the most precise devices, the uncertainty in the measurement continues to exist. Thus, in general, the greater the precision in the measurement of one of these magnitudes, the greater the uncertainty in the measure of the other complementary variable.  

Therefore the correct option is C.

7 0
3 years ago
A stone was dropped off a cliff and hit the ground with a speed of 88 ft/s . What is the height of the cliff? (Use 32 ft/s 2 for
bulgar [2K]

To solve this problem we will apply the linear motion kinematic equations, which describe the change in velocity, depending on the acceleration and the distance traveled, that is,

v_f^2 = v_i^2 +2ah

Where,

v_f= Final Velocity

v_i = Initial Velocity

a = Acceleration

h = height

Our values are given as,

v_f = 88 ft/s\\v_i = 0 ft /s\\a = 32 ft/s^2\\

Replacing we have,

vf^2 = vi^2 + 2*a*h

88^2 = 0 + 2*32*h

h= 121 ft

Therefore the height of the cliff is 121ft

5 0
3 years ago
A rifle with a mass of 0.9 kg fires a bullet with a mass of 6.0 g (0.006 kg). The bullet moves with a muzzle velocity of 750 m/s
SCORPION-xisa [38]

Answer:

a )  4.5 N.s

b) V =5 m/s    

Explanation:

given,

mass of rifle(M)  = 0.9 kg

mass of bullet(m)  = 6 g = 0.006 kg

velocity of the bullet(v)  = 750 m/s

a) momentum of bullet = m × v

                                  = 750 × 0.006

                                  = 4.5 N.s

b) recoil velocity                                                      

m × u + M × U = m × v + M × V

0  + 0  = 0.006 × 750 -  0.9 × V

V = \dfrac{4.5}{0.9}

V =5 m/s                    

 

5 0
3 years ago
Does anyone know the answer
scoundrel [369]
No put false I am right
7 0
3 years ago
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