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3 years ago

Why does a cell phone have more mass than a feather?

1 answer:

3 0

Well, this is actually simple. The general rule to the world when it comes to mass: The more space an object takes up, the more mass it has. Quite obviously, a cell phone would take up considerably more space than a feather would.
~Hope this helps!

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Is grape juice a solution or a mixture

svetlana [45]

Most definitely a mixture because it's usually a mix of puréed grapes,water,and sugar.

3 0

3 years ago

Read 2 more answers

The boiling points for a set of compounds in a homologous series can be qualitatively predicted using intermolecular force stren

shepuryov [24]

Answer:

The answer to your question is below

Explanation:

Alkane Formula Boiling point (°C)

Methane CH₄ -162

Ethane CH₃CH₃ - 89

Propane CH₃CH₂CH₃ - 42

Butane CH₃(CH₂)₂CH₃ - 0.5

Pentane CH₃(CH₂)₃CH₃ 36

Hexane CH₃(CH₂)₄CH₃ 69

Heptane CH₃(CH₂)₅CH₃ 98

Octane CH₃(CH₂)₆CH₃ 126

Nonane CH₃(CH₂)₇CH₃ 151

Decane CH₃(CH₂)₈CH₃ 174

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4 years ago

Which BEST describes the role of mitochondiſa in maintaining homeostasis for the cell?

spin [16.1K]

Answer: D

Explanation:

The mitochondria is the power house of the cell, remember power as energy

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3 years ago

Atrazine is an herbicide widely used for corn and is a common groundwater pollutant in the corn-producing regions of the United

riadik2000 [5.3K]

Answer:

0.94

Explanation:

Let's assume that the total sample of the soil is 1 cm³; which has a porosity of 0.4 cm³; then the original sample of the soil will be 0.6 cm³

The mass of the soil particles in 1 cm³ of soil + water = 0.75 g

The fraction of the total atrazine can be calculated by the expression;

Total atrazine = $C_w(\frac{g}{mL})*V_w(mL)+C_{(soil)}(\frac{g}{soil})*M_{(soil)}(gsoil)$

Also; $C_{(soil)}(\frac{g}{soil})= K_{oc}(\frac{mL}{gOC})*f_{oc} (\frac{gOC}{gsoil})*C_w(\frac{g}{mL})$

NOTE THAT: $K_{oc}( \frac{mL}{gOC})=K_{oc}\frac{L}{kgOC}$

Total atrazine can now be calculated as:

$C_w*0.4+K_{oc}f_{oc}C_w*0.75$ = $\frac{C_{soil}*M_{soil}}{Total atrazine}$

$=\frac{K_{oc}f_{oc}C_w*M_{soil}}{C_w*0.4+K_{oc}f_{oc}C_w*0.75} = \frac{0.75*K_{oc}f_{oc}}{0.4+K_{oc}f_{oc}*0.75}$

$= \frac{10^{2.52}*0.025*0.75}{0.4+10^{2.52}*0.025*0.75}$

= 0.94

Thus,the fraction of total atrazine that will be adsorbed to the soil = 0.94.

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4 years ago

Animals with reproduction dependent on internal fertilization need all of the following except

Elenna [48]

Internal development of embryos.

6 0

3 years ago