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gizmo_the_mogwai [7]
3 years ago
13

¿Qué sucede cuando dos sustancias se juntan?

Chemistry
1 answer:
Doss [256]3 years ago
6 0
Se produce un cambio químico cuando se mezclan dos sustancias y se transforman en una tercera sustancia.
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Each cell in an organism contains a set of hereditary information that gets passed from one generation to the next. The genes in
GrogVix [38]

Answer:

D

Explanation:

Offspring receive genes from both parents, they don't always have a recessive or dominant train but if they do have a dominant trait, it will always show while the recessive will only show if there is no dominant trait. For example: DD, Dr, and rr (D= dominant r = recessive)

8 0
3 years ago
Read 2 more answers
A vessel with a volume of 32. 5 l contains 2. 80 g of n2 gas, 0. 403 g of h2 gas, and 79. 9 g of ar gas. at 25°c, what is the to
d1i1m1o1n [39]

The total pressure of the gases in the vessel is found out by using the partial pressures of individual gases and adding them up. The total pressure of the gases in the vessel is 1.72 atm.

The Partial pressure of the gases is the individual pressure of the gases present in a vessel containing a mixture of gases. The total pressure can be found out by adding partial pressure of all gases.

Given:

Volume of vessel, V= 32.5L

Mass of Nitrogen gas = 2.8g

Mass of Hydrogen gas = 0.403g

Mass of Argon gas = 79.9g

We know that:

             Molar Mass of Nitrogen gas = 28g

             Molar Mass of Hydrogen gas = 2g

             Molar Mass of Argon gas = 40g

∴ Moles of gas = Given mass / Molar mass

∴ Using the Ideal Gas Equation:

PV = nRT

where, P is the Pressure of gas

V is the volume of gas

n is the moles of gas

R is the Universal Gas constant

T is the temperature

Applying the above equation of all three gases indivudually,

∴ For Nitrogen,

P₁V = n₁RT                    

⇒ P₁ × 32.5 = 2.8/28 × 0.082 × 298

⇒ P₁ = 0.07atm

∴ For Hydrogen,

P₂V = n₂RT                    

⇒ P₂ × 32.5 = 0.4/2 × 0.082 × 298

⇒ P₂ = 0.15 atm

∴ For Argon,

P₃V = n₃RT                    

⇒ P₃ × 32.5 = 79.9/40 × 0.082 × 298

⇒ P₃ = 1.5 atm

∴ Total pressure of vessel, P = P₁ + P₂ + P₃

                                         P = 1.72 atm

The total pressure of the gases in the vessel is 1.72 atm.

Learn more about Partial pressure here, brainly.com/question/23841760

#SPJ4

6 0
1 year ago
Explain how to identify a metal from visual observations
yarga [219]
I am a blacksmith, I would know this one. Alright... Aluminum, has a great shine to it, and it looks like silver... Same with tin, except aluminum is super shiny and sleek, while tin has a dull shine to it. Steel, is flat (color-wise), and it has a slight shine to it.
You can find what type of metal it is by color, shine, light reflectance, dullness, and several other properties. Hope I helped you! :)
4 0
3 years ago
Complete and balance the following equation: S(s)+HNO3(aq)→H2SO3(aq)+N2O(g)(acidic solution)
meriva

Answer:- The balanced equation is, 2HNO_3(aq)+2S(s)+H_2O(l)\rightarrow N_2O(g)+2H_2SO_3(aq) .

Solution:- Oxidation number of S is increasing from 0 to 4 and so it is oxidation. Oxidation number of N is decreasing from 5 to 1 and so it is reduction.

We write the oxidation and reduction half equations and balance them. The given reaction is taking place in an acidic medium.

First of all we balance all the atoms other than H and O. Then oxygen is balanced by adding H_2O and hydrogen is balanced by adding H^+ . Charge is balanced by adding electrons.

To makes the electrons equal for both the half equations we multiply the equation/equations by appropriate numbers.

Oxidation half equation:

S(s)\rightarrow H_2SO_3(aq)

S is already balanced. To balance O, we need to add three water molecules to the left side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)

For balancing hydrogen, we need to add 4 hydrogen ions to the right side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)+4H^+(aq)

Now to balance the charge we need to add 4 electrons to the right side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)+4H^+(aq)+4e^-

Reduction half equation:

HNO_3(aq)\rightarrow N_2O(g)

To balance N, we need to multiply left side by 2:

2HNO_3(aq)\rightarrow N_2O(g)

For balancing oxygen, we need to add 5 water molecules to the right side:

2HNO_3(aq)\rightarrow N_2O(g)+5H_2O(l)

To balance hydrogen, we need to add 8 hydrogen ions to the left side:

2HNO_3(aq)+8H^+(aq)\rightarrow N_2O(g)+5H_2O(l)

Now, for charge balance, we need to add 8 electrons to the left side:

2HNO_3(aq)+8H^+(aq)+8e^-\rightarrow N_2O(g)+5H_2O(l)

First half equation has 4 electrons and second half equation has 8 electrons.

To make the electrons equal, we need to multiply oxidation half equation by 2:

2S(s)+6H_2O(l)\rightarrow 2H_2SO_3(aq)+8H^+(aq)+8e^-

Now we add both of these two half equations and cancel out common species. What we get on doing this is:

2HNO_3(aq)+2S(s)+H_2O(l)\rightarrow N_2O(g)+2H_2SO_3(aq)



6 0
3 years ago
Read 2 more answers
You need to prepare 250.0 mL of a 1.35 M HCl solution from a 2.00 M HCl stock solution.
Lyrx [107]

Answer:

a. C. volumetric flask

b. B. Measure out x mL using a volumetric pipet

c. 168.75mL

d. B. Add the correct amount of stock solution then fill to the 250 mL mark with water.

Explanation:

  • The volumetric flask is mainly used in analytical chemistry to contain standard solutions or to prepare dilutions of a certain concentration of a reagent.
  • The volumetric pipette is used to deliver a given volume with greater precision and accuracy.
  • To make a dilution, the formula C1*V1 = C2*V2 is used where C is the concentration of the solution, in this case of molarity. V is the volume of the solution in ml and terms 1 and 2 correspond to the concentrated and diluted solutions respectively.

V2=\frac{1.35M*250mL}{2.00M} =168.75mL

8 0
4 years ago
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