All categories

3 years ago

A car increases velocity from 30 m/s to 60 m/s in 4 seconds. Calculate the average acceleration of the car over this time.

Physics

1 answer:

Lilit [14]3 years ago

3 0

Answer:

B.7.5m/s2

Explanation:

average acceleration=change invelocity/time taken

a=(60-30)/4

=7.5m/s2

You might be interested in

When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s

Aleksandr-060686 [28]

Answer:

$k = 457333.3 N/m$

$x_a =0.09\ m$

Explanation:

From the question we are told that

The total mass of three people is $M = 2.00*10^{2} \ kg$

The mass of the car is $m_c = 1.200 *10^{3} \ kg$

The compression of the car spring is $x = 3 \ cm = 0.03 \ m$

Generally the spring constant is mathematically represented as

$k = \frac{F}{x}$

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as

=> $F = (M +m_c) *g$

=> $F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8$

=> $F = 13720 \ N$

$k = \frac{13720}{0.03}$

=> $k = 457333.3 N/m$

Generally if the mass which the car is loaded with is $m = 3.00*10^{2} \ kg$

Then the force experienced by the spring is

=> $F_a = (m +m_c) *g$

=> $F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8$

=> $F_a = 41160 \ N$

Generally from the above formula the compression is

$x_a = \frac{F_a}{k}$

=> $x_a = \frac{41160}{457333.3}$

=> $x_a =0.09\ m$

3 0

3 years ago

The acceleration of a particle is given by ax(t) = -(2.00 m/s2) + (2.70 m/s3)t. (a) find the initial velocity v0x, such that the

Alexeev081 [22]

I’ll solve them right now just wait a few

3 0

3 years ago

In Millikan's oil-drop experiment, one looks ata small oil drop held motionless between two plates. Take the voltage betwee the

AleksandrR [38]

Answer:

The charge on the drop is

q = 1.741 x 10 ⁻²¹ C

Explanation:

Electric field due to plates

Ef = V/d

Ef = 2033 V / (2.0 * 10^-2 m )

Ef = 101650 V/m

So, we can write

Ef * q = m*g

q = m*g / E f

The mass can be equal using the density and the volume so:

m = ρ * v

The volume can be find as:

v = 2.298 x 10 ⁻ ¹⁶ m³

q = ρ * v * g / Ef

q = 81 x 10 ³ kg/ m³ * 2.2298 x 10 ⁻ ¹⁶ m³ * 9.8 m/s² / 101650 V/m

The charge on the drop is

q = 1.741 x 10 ⁻²¹ C

5 0

2 years ago

Which of the following best describes a coastal plain?

evablogger [386]

Area near a sea having flat land and low relief

5 0

2 years ago

Read 2 more answers

Find the acceleration produced.

krok68 [10]

Answer:

0.67m/s²

Explanation:

Given parameters:

Mass of toy = 1.2kg

Force applied = 0.8N

Unknown:

Acceleration = ?

Solution:

According to newton's second law of motion;

Force = mass x acceleration

Now,

Acceleration = $\frac{Force}{mass}$

Acceleration = $\frac{0.8}{1.2}$ = 0.67m/s²

4 0

3 years ago

Read 2 more answers