A space ship has four thrusters positioned on the top and bottom, and left and right as shown below. The thrusters can be operat
ed independently or together to help the ship navigate in all directions.
Initially, the Space Probe is floating towards the East, as shown below, with a velocity, v. The pilot then turns on thruster #2.
Select one:
a.
Space ship will have a velocity to the West and will be speeding up.
b.
Space ship will have a velocity to the East and will be speeding up.
c.
Space ship will have a velocity to the East and will be slowing down.
d.
Space ship will have a velocity to the West and will be slowing down.
e.
Ship experiences no change in motion.
Initially, the Space Probe is floating towards the East, as shown below, with a velocity, v. The pilot then turns on thruster #2.
Select one:
a.
Space ship will have a velocity to the West and will be speeding up.
b.
Space ship will have a velocity to the East and will be speeding up.
c.
Space ship will have a velocity to the East and will be slowing down.
d.
Space ship will have a velocity to the West and will be slowing down.
e.
Ship experiences no change in motion.
1 answer:
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Answer:
g₂ = 11 m/s²
Explanation:
The value of free-fall acceleration on the surface of a planet is given by the following formula:
where,
g = free-fall acceleration
G = Universal Gravitational Constant
m = mass of the planet
r = radius of planet
FOR PLANET 1:
--------------------- equation (1)
FOR PLANET 2:
using equation (1):
<u>g₂ = 11 m/s²</u>
Answer:
(a)
(b)
Solution:
As per the question:
Side of the cube, a = 4.4 cm
Coordinates of the diagonally opposite corner, A = <4.4, 4.4, 4.4> cm
Now,
(a) To calculate the unit vector:
(b) To calculate the angle between the two vectors say A and A' is given by:
(1)
Now,
The coordinates of the diagonally opposite corner, A' is <0, 0, 1> cm
Thus
Now,
Using equation (1) :
Thus
Answer:
The net force = 0
Explanation:
The given information includes;
The mass of the crate = 250 kg
The way the helicopter lifts the crate = Uniformly (constant rate (speed), no acceleration)
In order to pull the crate upwards, the helicopter has to provide a force equivalent to the weight of the crate keeping the helicopter on the ground.
The weight of the crate = The mass of the crate × The acceleration due gravity acting on the crate
The weight of the crate, ↓ = 250 kg × 9.81 m/s² = 2,452.5 N
The force the helicopter should provide to just lift the crate, ↑ = The weight of the crate = 2,452.5 N
The net force, =
↑ -
↓ = 2,452.5 N - 2,452.5 N = 0
The net force = 0.