Answer:
34 m/s
Explanation:
m = Mass of glider with person = 680 kg
v = Velocity of glider with person = 34 m/s
= Mass of glider without person = 680-60 kg
= Gliders speed just after the skydiver lets go
= Mass of person = 60 kg
= Velcotiy of person = 34 m/s
As the linear momentum of the system is conserved
![m_1v_1+m_2v_2=mv\\\Rightarrow v_1=\dfrac{mv-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{680\times 34-60\times 34}{680-60}\\\Rightarrow v_1=34\ m/s](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3Dmv%5C%5C%5CRightarrow%20v_1%3D%5Cdfrac%7Bmv-m_2v_2%7D%7Bm_1%7D%5C%5C%5CRightarrow%20v_1%3D%5Cdfrac%7B680%5Ctimes%2034-60%5Ctimes%2034%7D%7B680-60%7D%5C%5C%5CRightarrow%20v_1%3D34%5C%20m%2Fs)
The gliders speed just after the skydiver lets go is 34 m/s
Answer:
They are 7.4m apart.
Explanation:
Here we have a parabolic motion problem. we need the time taken to land so:
![Y=Yo+Vo*t+\frac{1}{2}*a*t^2](https://tex.z-dn.net/?f=Y%3DYo%2BVo%2At%2B%5Cfrac%7B1%7D%7B2%7D%2Aa%2At%5E2)
considerating only the movement on Y axis:
![0=4.6-(9.81)*t^2\\t=0.68s](https://tex.z-dn.net/?f=0%3D4.6-%289.81%29%2At%5E2%5C%5Ct%3D0.68s)
Because we have a contant velocity motion on X axis:
![xs=vs*t\\xs=17m/s*(0.68s)\\xs=11.6m](https://tex.z-dn.net/?f=xs%3Dvs%2At%5C%5Cxs%3D17m%2Fs%2A%280.68s%29%5C%5Cxs%3D11.6m)
and
![xg=vg*t\\xg=28m/s*(0.68s)\\xg=19m](https://tex.z-dn.net/?f=xg%3Dvg%2At%5C%5Cxg%3D28m%2Fs%2A%280.68s%29%5C%5Cxg%3D19m)
the distance between them is given by:
![d=|xg-xs|\\d=7.4m](https://tex.z-dn.net/?f=d%3D%7Cxg-xs%7C%5C%5Cd%3D7.4m)
Answer:
This galaxy belongs to the elliptical galaxy category. This is because it does not have spiral arms.
Answer:
Electrons are so small that it does not affect the mass of atom .
Explanation:
Electrons are much smaller in mass than protons, weighing only 9.11 × 10^-28 grams, or about 1/1800 of an atomic mass unit. Therefore, they do not contribute much to an element's overall atomic mass.