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3 years ago

Les

Physics

1 answer:

fomenos3 years ago

8 0

Explanation:

I'm corona positive and isolated feeling depressed just logged in to talk someone but people ignoring me thanks for this behaviour got disappointed bye everyone logging out had a great time

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What type of energy is it when rain falls?

IRISSAK [1]

Answer:

The falling raindrop is converting gravitational PE into KE and thermal energy through resistance. The PE is from solar energy evaporating the liquid water to vapor and powering the weather that formed the cloud.

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3 years ago

A toy floats in a swimming pool. The buoyant force exerted on the toy depends on the volume ofa. none of these choices.b. all th

Citrus2011 [14]

Answer:c

Explanation:

The buoyancy force on toy depends upon the volume of toy under pool water.

According to Archimedes principle buoyant force on a floating body depends upon the weight of displaced liquid by object.

Buoyancy force is given by

$F_b=\rho _f\times V\times g$

where $\rho _f$ =density of fluid

V=volume of object under water

g=acceleration due to gravity

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3 years ago

The critical angle for refraction from glass to air is 30° and that from water to air is 37°.Find the critical angle for refract

erik [133]

Answer:

1,55

5 400 Å

193548,4 km/s

1,55

3 10 m/s

Vidrio v: =

3 724,14 Å

1,45

5 400 Å

206 896,5 km/s

1,45

3 10 m/s

Aceite = v:

07,1

45,1

55,1

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3 years ago

Suppose a vacuum cleaner uses 120 J of electrical energy. If 45 J are used to pull air into the vacuum cleaner, how efficient is

Zigmanuir [339]

Efficiency = 45J/120J = 0.375

Or

0.375 * 100% = 37.5 %

3 0

3 years ago

A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va

makkiz [27]

Answer:

a) In a parallel plate capacitor the capacitance is

$C = \frac{Q}{V} = \epsilon_0\frac{A}{d}$

So, in order to halve the capacitance the plate separation should be twice the original distance.

b) Same question as (a).

c) According to the above equations, the charge stored in a capacitor is directly proportional to the plate separation.

$\frac{Q}{V} = \frac{A}{d}$

In order to halve the charge stored the plate separation should be half the original distance.

d) Same question as (c).

e) The energy stored in a capacitor is

$U = \frac{1}{2}CV^2 = \frac{1}{2}\epsilon_0\frac{A}{d}(Ed)^2 = \frac{1}{2}\epsilon_0AE^2d$

In order to halve the energy stored in the capacitor, the plate separation should be twice the original distance.

f) Same question as (e).

g) The energy density is given by the following equation

$u = \frac{\frac{1}{2}CV^2}{Ad} = \frac{\frac{1}{2}\epsilon_0\frac{A}{d}(E^2d^2)}{Ad} = \frac{1}{2}\epsilon_0E^2.$

As it turns out, the energy density is independent from the geometric factors. This makes sense, because the electric field in a parallel field capacitor is independent from the distance.

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3 years ago