1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kenny6666 [7]
2 years ago
9

Les

Physics
1 answer:
fomenos2 years ago
8 0

Explanation:

I'm corona positive and isolated feeling depressed just logged in to talk someone but people ignoring me thanks for this behaviour got disappointed bye everyone logging out had a great time

You might be interested in
What is the potential difference across lamp 1
Alex73 [517]

Answer:

1+1=2

Explanation:

You just need to add and voila the answer

7 0
2 years ago
TECHNOLOGY A Lamborghini Aventador accelerates from rest to 100 km / h in 2.9 s. The mass of the car is 1575 kg Calculate the po
DerKrebs [107]

At 100 km/hr, the car's kinetic energy is

KE = (1/2) (mass) (speed)²

KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²

KE = (787.5 kg) (27.78 m/s)²

KE = 607,639 Joules

In order to deliver this energy in 2.9 seconds, the engine must supply

(607,639 J / 2.9 sec) = 209,531 watts

<em>Power = 281 HP</em>

6 0
3 years ago
What tool is used to determine the mass of an object?
melisa1 [442]
A Beam balance (or Beam scale) is a device to measure weight or mass. These are also known as mass scales, weight scales, mass balances, weight balances, or simply scales, balances, or balance scales. You can also use a graduated cylinder and determine the water displaced and figure out the mass of an object this way!

- if this answer is what you were looking for, don’t forget to heart and maybe if you really liked it brainliest :)
3 0
3 years ago
If you remove large amounts of heat from a liquid, what could happen
snow_lady [41]
A liquid becomes a solid when energy is removed. The energy content decreases, and the speed of the particles decrease.
3 0
3 years ago
Determine the lamp wattage required to obtain an illumination level of 50 f-c over a 100 ft2 area if a fixture is used with a CU
Bezzdna [24]

Lamp Wattage is utilized with a CU of 0.75 and 80 percent of the available light reaches the work surface, the remaining 20 percent is absorbed by walls and other objects in the space, resulting in an illumination level of 50 f-c over a 100 ft2 area

The term "lumen" refers to the emission of "luminous flux," which is a measurement of the total amount of visible light emitted by a source in a certain amount of time. The illumination level over a 100 ft2 area will be 50 f-c Lamp Wattage with a CU of 0.75 used, with 80 percent of the available light reaching the work surface and the remaining 20 percent being absorbed by walls and other objects in the room.
Total Lamp Wattage = Number of Lamps X Wattage of Each Lamp.
The fixtures' total wattage is 2 x 32, or 64 watts.
Lumen per Fixtures equals Lumen Efficiency (Lumen per Watt) times the Watt of each Fixture
85x 64 = 5440 lumens per fixture.

To learn more about lamp wattage please visit -
brainly.com/question/27154431
#SPJ4

3 0
2 years ago
Other questions:
  • Can the earth sustain our infinite wants with its finite amount of resources? explain.
    13·1 answer
  • What are real images? Are the upright or inverted?
    11·1 answer
  • The organization of former British colonies that includes Canada, India, Pakistan, and other countries is called the __________.
    9·2 answers
  • Can someone please help me on this!!!
    15·1 answer
  • The smallest level of organization in living things is
    13·1 answer
  • A horse pulls on a carriage. By Newton's third law, the carriage pulls back on the horse with equal force. Why do the action and
    5·1 answer
  • A student watches a video about forces.
    6·1 answer
  • Compound name: for C3N6
    15·1 answer
  • The type of brightness in which all
    13·1 answer
  • When a scientific calculator shows the quantity below, what does it mean?<br> 1.5E8
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!