Question

A pivot at one end supports a beam of uniform density. Archimedes attaches a cable to the beam 1.25 m from its pivoted end. The cable makes an angle of 25.0° with respect to the beam. The beam is 5.00 m in length and has a mass of 100.0 kg. The pivot exerts significant forces on the end of the beam. Which one of the following choices best describes the magnitude of the tension in the cable?
A. 1855 N.
B. 4638 N.
C. 1960 N.
D. 2319 N.
E. 980 N.

Answer 1

Answer:

B.4638 N

Explanation:

We are given that

Distance of cable from its pivot end=1.25 m

$\theta=25^{\circ}$

Length of beam=5 m

Half length of beam=$\frac{5}{2}=2.5 m$

Mass =m=100 kg

We have to find the magnitude of tension in the cable .

According to question

$Tsin25\times 1.25=100\times 9.8\times 2.5$

$T=\frac{100\times 9.8\times 2.5}{sin25\times 1.25}$

$T=4638 N$

Hence,option B is true.