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3 years ago

11

Object C has a mass of 3,600 kilograms. Object D has a mass of 900 kilograms. Both objects were placed on different planets so t

hat their weights are equal. The gravity acting on Object C is _____ times the gravity acting on Object D.

2 answers:

Morgarella [4.7K]3 years ago

8 0

Answer:

1/4

Explanation:

The weight of an object is given by:

$W=mg$

where m is the mass of the object and g is the acceleration due to gravity on the planet.

We are told that object C and object D have same weight, so we can write:

$m_C g_C = m_D g_D$

where:

$m_C = 3600 kg$ is the mass of object C

$m_D = 900 kg$ is the mass of object D

We can re-arrange the equation to find a relationship between the gravity acting on object C and the gravity acting on object D:

$g_C = \frac{m_D}{m_C}g_D = \frac{900 kg}{3600 kg}g_D = \frac{1}{4}g_D$

So, the gravity acting on object C is 1/4 times the gravity acting on object D.

jek_recluse [69]3 years ago

7 0

The answer is 1/4
this is actually a very simple question because if you divide 3,600 by 4 that equals 900 so if you want them to be the same waight you need 3,600 to be multiplied by 1/4.

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Answer:

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3 years ago

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Over [174]

Answer:

Part a)

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Part b)

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Part c)

$F_c = 5.5 N$

Explanation:

Part a)

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Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

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If Alex push from other side then also the acceleration will be same

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$F_c = 5.5 N$

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