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krek1111 [17]
3 years ago
6

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to i

ts position?
Physics
2 answers:
Naily [24]3 years ago
5 0

Answer: 137.2 J

Explanation:

The gravitational potential energy of the bowling ball is given by:

U=mgh

where

m = 7.00 kg is the mass of the ball

g = 9.80 m/s^2 is the acceleration due to gravity

h = 2.00 m is the height above the ground

Substituting, we find

U=(7.00 kg)(9.8 m/s^2)(2.00 m)=137.2 J

deff fn [24]3 years ago
4 0
mgh =7*2*9.8=137.2. It should be the answer.
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Given Information:  

Resistance of circular loop = R = 0.235 Ω 

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Explanation:  

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Answer:

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