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3 years ago

6

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to i

ts position?

2 answers:

Naily [24]3 years ago

5 0

Answer: 137.2 J

Explanation:

The gravitational potential energy of the bowling ball is given by:

$U=mgh$

where

m = 7.00 kg is the mass of the ball

g = 9.80 m/s^2 is the acceleration due to gravity

h = 2.00 m is the height above the ground

Substituting, we find

$U=(7.00 kg)(9.8 m/s^2)(2.00 m)=137.2 J$

deff fn [24]3 years ago

4 0

mgh =7*2*9.8=137.2. It should be the answer.

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iris [78.8K]

To solve this problem we will apply the concepts related to the Electrostatic Force given by Coulomb's law. This force can be mathematically described as

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Here

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$F_{12} = \frac{(9*10^9 Nm^2/C^2)(1*10^{-6} C)(-6*10^{-6} C)}{(1 m)^{2}}$

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3 years ago

An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields a

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v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

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3 years ago

Which is not an example of a scalar?

Crank

Answer:

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A scalar has only magintude, not direction

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Nostrana [21]

<u><em>The question doesn't provide enough data to be solved, but I'm assuming some magnitudes to help you to solve your own problem</em></u>

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