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krek1111 [17]
4 years ago
6

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to i

ts position?
Physics
2 answers:
Naily [24]4 years ago
5 0

Answer: 137.2 J

Explanation:

The gravitational potential energy of the bowling ball is given by:

U=mgh

where

m = 7.00 kg is the mass of the ball

g = 9.80 m/s^2 is the acceleration due to gravity

h = 2.00 m is the height above the ground

Substituting, we find

U=(7.00 kg)(9.8 m/s^2)(2.00 m)=137.2 J

deff fn [24]4 years ago
4 0
mgh =7*2*9.8=137.2. It should be the answer.
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3 years ago
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3 years ago
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AURORKA [14]

The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g

<h3>What is Mass and Weight ?</h3>

Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.

What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?

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