Question

A 7.00 kg bowling ball is held 2.00 m above the ground. Using g = 9.80 m/s2, how much energy does the bowling ball have due to its position?

Answer 1

Answer: 137.2 J

Explanation:

The gravitational potential energy of the bowling ball is given by:

$U=mgh$

where

m = 7.00 kg is the mass of the ball

g = 9.80 m/s^2 is the acceleration due to gravity

h = 2.00 m is the height above the ground

Substituting, we find

$U=(7.00 kg)(9.8 m/s^2)(2.00 m)=137.2 J$

Answer 2

mgh =7*2*9.8=137.2. It should be the answer.