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earnstyle [38]
3 years ago
12

According to the definition of mechanical work, pushing on a rock accomplishes no work unless there is

Physics
2 answers:
nignag [31]3 years ago
6 0
Movement in the same direction as the diection of the force
LekaFEV [45]3 years ago
4 0
There must be movement in the same direction as the force put on the object. Hope this helps!
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You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 1515 lb and was trav
serious [3.7K]

what was the speed limit, and it was 40 mph


6 0
3 years ago
Block 1 (mass 2.00 kg) is moving rightward at 10.0 m/s and block 2 (mass 5.00 kg) is moving rightward at 3.00 m/s. The surface i
DaniilM [7]

Answer:

a) 0.25m

b) 5 m/s

Explanation:

When the spring is compressed both boxes are moving with the same velocity, so applying the principle of linear momentum conservation:

m1*v_{o1}+m2*v_{o2}=(m1+m2)*v\\v=5m/s

Now applying the principle of energy conservation:

K1+K2+U_{g1}-U_e=Kf+U_{g2}\\K1+0-U_e=K2+0\\U_e=K1+K2-kf\\\frac{1}{2}*k*x^2+=\frac{1}{2}*m1*v1^2+\frac{1}{2}*m1*v1^2-\frac{1}{2}*(m1+m2)*v^2\\\\x=\sqrt{\frac{2.00kg*(10m/s)^2+5.00kg*(3.00m/s)^2-7.00kg*(5m/s)^2}{1120N/m}}\\x=0.25m

We got that the maximum compression is 0.25m.

5 0
3 years ago
A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera
Fantom [35]
In order to accelerate the dragster at a speed v_f = 100 m/s, its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
W= K_f - K_i = K_f =  \frac{1}{2}mv_f^2=2.5 \cdot 10^6 J

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is -W_f:
W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:
P= \frac{W}{t}= \frac{2.98 \cdot 10^6 J}{7.30 s}=4.08 \cdot 10^6 W

And since 1 horsepower is equal to 746 W, we can rewrite the power as
P=4.08 \cdot 10^6 W \cdot  \frac{1 hp}{746 W} =547 hp



3 0
4 years ago
Read 2 more answers
What happens to the Force due to gravity between 2 masses if one
creativ13 [48]
There is half the force that there was before it was split in half
7 0
3 years ago
HEre now can somebody help!! <br> Pic is what i need help with
AleksAgata [21]

Answer:

which of the cars are speeding up: c

which of the cars or slowing down: a

which of the cars are maintaning a constant speed: b

Explanation:

8 0
2 years ago
Read 2 more answers
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