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earnstyle [38]
3 years ago
12

According to the definition of mechanical work, pushing on a rock accomplishes no work unless there is

Physics
2 answers:
nignag [31]3 years ago
6 0
Movement in the same direction as the diection of the force
LekaFEV [45]3 years ago
4 0
There must be movement in the same direction as the force put on the object. Hope this helps!
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Moon A has a mass of 3M and a radius of 2R. Moon B has a mass of 4M and a radius of R. What is the ratio of the force of gravita
zubka84 [21]

Answer:

c

Explanation:

5.3" (and any subsequent words) was ignored because we limit queries to 32 words.

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2 years ago
Another name for Newton’s 2nd law
monitta
According to Newton’s second law of motion, also know as the law of force and Accelerate , a force upon an object causes it to accelerate according to the formula net force = mass x acceleration
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2 years ago
Calculate the force of gravity between planet X and planet y if both planets are 3.75 X 10^11 m apart, planet X has a mass of 1.
GenaCL600 [577]

So, the force of gravity that the asteroid and the planet have on each other approximately \boxed{\sf{2.9 \times 10^{17} \: N}}

<h3>Introduction</h3>

Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

\boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}}

With the following condition :

  • F = gravitational force (N)
  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_1} = mass of the first object (kg)
  • \sf{m_2} = mass of the second object (kg)
  • r = distance between two objects (m)

<h3>Problem Solving</h3>

We know that :

  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_X} = mass of the planet X = \sf{1.55 \times 10^{22}} kg.
  • \sf{m_Y} = mass of the planet Y = \sf{3.95 \times 10^{28}} kg.
  • r = distance between two objects = \sf{3.75 \times 10^{11}} m.

What was asked :

  • F = gravitational force = ... N

Step by step :

\sf{F = G \times \frac{m_X \times m_Y}{r^2}}

\sf{F = 6.67 \cdot 10^{-11} \times \frac{1.55 \cdot 10^{22} \cdot 3.95 \times 10^{28}}{(3.75 \times 10^{11})^2}}

\sf{F \approx \frac{40.84 \times 10^{-11 + 22 + 28}}{14.0625 \times 10^{22}}}

\sf{F \approx 2.9 \times 10^{39 - 22}}

\sf{F \approx 2.9 \times 10^{17} \: N}

<h3>Conclusion</h3>

So, the force of gravity that the asteroid and the planet have on each other approximately

\boxed{\sf{2.9 \times 10^{17} \: N}}

<h3>See More</h3>
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1 year ago
Which situation is the best example of translational motion?.
AleksAgata [21]

Answer:

 a block sliding down a ramp,a leaf blowing across a field

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2 years ago
Which type of galaxy has the most active star formation?
UkoKoshka [18]
That answer is spiral galaxies
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3 years ago
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