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pickupchik [31]
3 years ago
9

HELPPP PLEASE URGENT

Physics
1 answer:
Shtirlitz [24]3 years ago
8 0
B i believe BUT IF IT DONT WORK IM SORRY LOLZ
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Explain two ways in which humans are related<br>to whales.​
Maksim231197 [3]

Answer:

humans and whales are both mammals

humans and whales can breathe air

4 0
3 years ago
Calculate the final speed of a 110-kg rugby player who is initially running at 8.00 m/s but collides head-on with a padded goalp
Contact [7]
<span>The answer is -0.8 m/s. We know acceleration is the average of final minus initial velocity over time (a = (vf-v0)/t). We also know that Force is equal to Mass times Acceleration (F = ma). Using our force equation, we know that the acceleration we get is negative 8.8 (-8.8). The force is acting in the opposite direction of the rugby player, hence the negative sign. From there, plug in that number for a in the velocity equation, and solve for vf, as v0 and t are known. We get 0.8 m/s in the opposite direction that the player was running.</span>
6 0
3 years ago
What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?
Archy [21]

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

I=\dfrac{E^2}{2\mu_{0}c}

E=\sqrt{2\times I\mu_{0}c}

Put the value into the formula

E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}

E=931.17\ N/C

Using formula of magnetic field

B = \dfrac{E}{c}

Put the value into the formula

B=\dfrac{931.17}{3\times10^{8}}

B=0.0000031039\ T

B=3.10\times10^{-6}\ T

(b). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using gravitational force

F=\dfrac{Gm_{s}M_{e}}{r^2}

Put the value into the formula

F=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}

F=3.522\times10^{22}\ N

We need to calculate the radiation force

Using formula of force

F_{R}=\dfrac{I}{c}\pi\timesR_{E}^{2}

Put the value into the formula

F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.378\times10^{6})^2

F_{R}=4.8\times10^{8}\ N

The gravitational and solar electromagnetic pressure forces of the sun on the earth

\dfrac{F_{G}}{F_{R}}=\dfrac{3.522\times10^{22}}{4.8\times10^{8}}

\dfrac{F_{G}}{F_{R}}=7.3375\times10^{13}

Hence, This is the required solution.

3 0
3 years ago
The pull is always toward the _____ of the planet
Nataly [62]
The correct answer is center. Hope this helps.
8 0
3 years ago
Read 2 more answers
(a) List the four classifications of steels. (b) For each, briefly describe the properties and typical applications.
tatiyna

Answer:

Type of steels and their uses :

Type                            Carbon percentage                           uses

Low carbon steel         0.1% to 0.3 %           Food cans ,car body ,nut & bolt.

Medium carbon steel    0.3% to 0.70 %   Metal chains ,wheel rims,wire ropes

High carbon steel         0.7% to 1.3%          Hammers,drills ,dies and taps.

High speed steel         0.6 %                     Cutting tools in lathe machine.

Type                                           Properties

Low carbon steel     -          Fairly strong and easily get rusty              

Medium carbon steel -       Having high hardness than low carbon steel

High carbon steel  -            Having high hardness than medium carbon steel

High speed steel  -             Harder ,can retain its shape at high temperature

4 0
4 years ago
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