Answer: The height of the fluid rise is 0.01m
Explanation:
Using the equation
h = (2TcosѲ )/rpg
h= height of the fluid rise
diameter of the tube =3mm
radius of the tube= 3/2 =1.5mm=0.0015
T= surface tension = 600mN/m=0.6N/m
Ѳ = contact angle = C
p= density =3.7g/cm3= 3700kg/m3
g= acceleration due to gravity =9.8m/s2
h = ( 2*0.6*0.5)/(0.0015*3700*9.8)
h = 0.6/54.39
h= 0.01m
Therefore,the height of the fluid rise is 0.01m
Answer:
1547.6 J
Explanation:
From the law of conservation of energy, the sum of initial and final energy is the same. Energy can only be transformed into other forms but can't be created nor lost
Initial kinetic energy of the hammer system is given by
where m is mass of the body and v is the velocity
Substituting m for mass of hammer which is 2.44 Kg and v for 62 m/s
Since the hammer comes to rest, the final kinetic energy is zero since it's velocity is zero
Change in kinetic energy is given by
hence 0-4689.68 J=-4689.68 J
Change in total internal energy is given by
and in this case the change in potential energy is zero
Since only 0.33 of this energy is converted hence