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horrorfan [7]
3 years ago
6

If an endothermic process absorbs 256j how many kilocalories are absorbed

Chemistry
2 answers:
Finger [1]3 years ago
8 0
There are several units for expressing energy, Most common are joules and kilocalories.

The conversion factor of joule to kilocalories is 
 1 kilo calorie  = 4184 J
∴ x kilo calorie = 256 J

x = \frac{256}{4184} = 0.0611 kilo calories

Thus, 256 J = 0.0611 kilocalories
astra-53 [7]3 years ago
5 0

Answer: 0.0612 kcalories

Explanation:

Endothermic processes are those processes in which heat is absorbed and exothermic processes are those processes in which heat is released.

Standard units for heat measurement are Joules and calories wherein

1 joule = 0.239 calorie.

As 1 Joule is equivalent to 0.239 calorie

256 Joules are equivalent to=\frac{0.239}{1}\times 256=61.2calories

Now 1 cal = 0.001 kcalories

Therefore 61.2 calories=\frac{0.001}{1}\times 61.2=0.0612kcal

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A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
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Answer:

V₁  = 374.71  mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

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T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁  = 456 mL × 295 K / 359 k

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