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vlada-n [284]
3 years ago
8

What happens to the efficiency of a ramp if friction is reduced?

Physics
1 answer:
love history [14]3 years ago
3 0
It's efficiency will increase
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A block of aluminum at a temperature of T1 = 32 degrees C has a mass of m1 = 12 kg. It is brought into contact with another bloc
Mariulka [41]

Answer:T=21.33 ^{\circ}

Explanation:

Given

mass of First Block m_1=12 kg

Temperature T_1=32^{\circ}

mass of second block m_2=0.5 m_1=6 kg

Temperature T_2=9^{\circ}

Heat capacity of aluminium c=899 J/kg-K

Final Temperature acquired by both blocks at steady state

Heat loss first block =Heat gain by second block

m_1\times c\times (32-T)=m_2\times c\times (T-9)

12\times 899\times (32-T)=6\times 899\times (T-9)

2\times 32=3T

T=\frac{64}{3}=21.33 ^{\circ}

5 0
3 years ago
For a relative frequency distribution, relative frequency is computed is computed as ____________.
Yuliya22 [10]

Answer:

For a relative frequency distribution, relative frequency is computed as the class frequency divided by the number of observations.

6 0
2 years ago
What is the difference between a neap and a spring tide in terms of size?
Mamont248 [21]
Spring tides occur when the moon is either new or full, and the sun, the moon, and the Earth are aligned. ... neap tide- A tide in which the difference between high and low tide is the least. Neap tides occur twice a month when the sun and moon are at right angles to the Earth.
7 0
3 years ago
An astronaut goes out for a space walk. Her mass (including space suit, oxygen tank, etc.) is 100 kg. Suddenly, disaster strikes
Marina CMI [18]

Answer:

<u>Part A:</u>

Unknown variables:

velocity of the astronaut after throwing the tank.

maximum distance the astronaut can be away from the spacecraft to make it back before she runs out of oxygen.

Known variables:

velocity and mass of the tank.

mass of the astronaut after and before throwing the tank.

maximum time it can take the astronaut to return to the spacecraft.

<u>Part B: </u>

To obtain the velocity of the astronaut we use this equation:

-(momentum of the oxygen tank) = momentum of the astronaut

-mt · vt = ma · vt

Where:

mt = mass of the tank

vt = velocity of the tank

ma = mass of the astronaut

va = velocity of the astronaut

To obtain the maximum distance the astronaut can be away from the spacecraft we use this equation:

x = x0 + v · t

Where:

x = position of the astronaut at time t.

x0 = initial position.

v = velocity.

t = time.

<u>Part C:</u>

The maximum distance the astronaut can be away from the spacecraft is 162 m.

Explanation:

Hi there!

Due to conservation of momentum, the momentum of the oxygen tank when it is thrown away must be equal to the momentum of the astronaut but in opposite direction. In other words, the momentum of the system astronaut-oxygen tank is the same before and after throwing the tank.

The momentum of the system before throwing the tank is zero because the astronaut is at rest:

Initial momentum = m · v

Where m is the mass of the astronaut plus the equipment (100 kg) and v is its velocity (0 m/s).

Then:

initial momentum = 0

After throwing the tank, the momentum of the system is the sum of the momentums of the astronaut plus the momentum of the tank.

final momentum = mt · vt + ma · va

Where:

mt = mass of the tank

vt = velocity of the tank

ma = mass of the astronaut

va = velocity of the astronaut

Since the initial momentum is equal to final momentum:

initial momentum = final momentum

0 = mt · vt + ma · va

- mt · vt = ma · va

Now, we have proved that the momentum of the tank must be equal to the momentum of the astronaut but in opposite direction.

Solving that equation for the velocity of the astronaut (va):

- (mt · vt)/ma = va

mt = 15 kg

vt = 10 m/s

ma = 100 kg - 15 kg = 85 kg

-(15 kg · 10 m/s)/ 85 kg = -1.8 m/s

The velocity of the astronaut is 1.8 m/s in direction to the spacecraft.

Let´s place the origin of the frame of reference at the spacecraft. The equation of position for an object moving in a straight line at constant velocity is the following:

x = x0 + v · t

where:

x = position of the object at time t.

x0 = initial position.

v = velocity.

t = time.

Initially, the astronaut is at a distance x away from the spacecraft so that

the initial position of the astronaut, x0, is equal to x.

Since the origin of the frame of reference is located at the spacecraft, the position of the spacecraft will be 0 m.

The velocity of the astronaut is directed towards the spacecraft (the origin of the frame of reference), then, v = -1.8 m/s

The maximum time it can take the astronaut to reach the position of the spacecraft is 1.5 min = 90 s.

Then:

x = x0 + v · t

0 m = x - 1.8 m/s · 90 s

Solving for x:

1.8 m/s · 90 s = x

x = 162 m

The maximum distance the astronaut can be away from the spacecraft is 162 m.

6 0
3 years ago
Is there ever a situation where an ant will have more momentum than an elephant? Explain why or why not? Question 2 options: Yes
sergiy2304 [10]

An ant can have more momentum than an elephant when the elephant is standing still.

Answer: A

Explanation

The momentum is the quantification of the movement done by an object.

It is found to be dependent on the mass of the object and the velocity with which it is moving.

In the present case, the ant has negligible mass compared to elephant so the momentum can be more for ant only when the velocity with which the elephant is moving tends to be zero.

As the velocity of elephant will be zero, the momentum of elephant will be zero so in this criteria, the moving ant will be having more momentum compared to elephant with zero velocity.

So an elephant with zero velocity means the elephant is standing still.

Thus, the condition in which the ant will be having more momentum compared to elephant is when the elephant stands still.

6 0
2 years ago
Read 2 more answers
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