All categories

4 years ago

Heeeeelp urgent I need an compare and contrast between energy and work. 20 pts.....

Physics

2 answers:

ddd [48]4 years ago

6 0

energy is the ability to do work while work is the dot product of force and displacement

grin007 [14]4 years ago

5 0

Work is done by applying force. Energy is the ability to perform work or an action. Both are smaller units and are related closely.

<u>Explanation: </u>

Work is an act of overpowering resistance.It is done by applying force. It acts as evidence of empowerment of resistance form the application of force movement.

The capability to perform some work or action is Energy. Energy can take different forms like light, electrical, heat, etc. The energy in motion is work. The energy changes form one form to another by the process of work. Work can be of only two forms. It can be either positive or negative.

You might be interested in

What is the effect on the force of gravity between two objects if the mass of one object remains unchanged while the distance to

drek231 [11]

Answer:

The force of gravity after you double the mass and the distance is half of the initial force: $F_{2}=\frac{1}{2}F_{1}$

Explanation:

The initial force of gravity is:

$F_{1}=\frac{Gm_{1}m_{2}}{r^2}$

where $G$ is the universal gravitational constant, $m_{1}$ is the mass of the first object, $m_{2}$ is the mass of the second object, and $r$ is the distance between the objects.

If the mass of the second object is doubled, now we have $2m_{2}$ , and if the distance between the objects is also doubled instead of $r$ now we have $2r$ .

So the force of gravity now is:

$F_{2}=\frac{Gm_{1}(2m_{2})}{(2r)^2}\\ F_{2}=\frac{2Gm_{1}m_{2}}{4r^2} \\F_{2}=\frac{1}{2} \frac{Gm_{1}m_{2}}{r^2}$

and we know that $F_{1}=\frac{Gm_{1}m_{2}}{r^2}$

so the new force of gravity is:

$F_{2}=\frac{1}{2}F_{1}$

The force of gravity after you double the mass and the distance is half of the initial force.

3 0

3 years ago

An ethylene glycol solution contains 25.4 g of ethylene glycol (C2H6O2) in 89.0 mL of water. (Assume a density of 1.00 g/mL for

Vaselesa [24]

Answer:

-7.44°C

Explanation:

Calculate the molality of the solution. Use the density of the solvent(water) as a conversion factor in order to convert from millilitres of solvent to grams of solvent. Then convert grams into kilograms. Finally, use the molar mass of ethylene glycol as a conversion factor to convert from grams to moles of ethylene glycol.

m = 25.4 g C2H6O2/89.0 mL solv

= 4.6321 C10H8O

Compute the freezing-point depression.

ΔT_f=K_f*m ==> (1.86°C)*(3.9996 m)

=7.44°C

Compute the freezing point of the solution by subtracting the freezing-point depression to the freezing point of the pure solvent.

freezing point =0.0°C-ΔT_f

= -7.44°C

8 0

3 years ago

1) Radiation from the sun can be deflected or contained by

earnstyle [38]

Answer:

Explanation:

light colors deflect ligjt

7 0

3 years ago

The largest centrifuge equipped for human testing at NASA is capable of

blagie [28]

I to have no clue as well

4 0

3 years ago

The metal wire is stretched so that its cross-section is still circular but its total length is now 10 meters. What is the resis

KATRIN_1 [288]

I don’t know I think about 20 meters but I’m probably wrong I just need to do this so someone can answer my question

3 0

3 years ago