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alukav5142 [94]
3 years ago
14

Why might a balloon, that is inflated almost to its capacity, pop or explode on an extremely warm day?

Physics
2 answers:
REY [17]3 years ago
7 0
On an extremely warm day, the balloon might pop because gases expand the hotter they get, and due to its temperature it is likely to pop if it is, indeed, nearly, if not completely, filled to its capacity.  I hope this helps, have a nice day!
nikitadnepr [17]3 years ago
4 0

Explanation:

On an extremely hot day, there will be thermal expansion of the object occur.

With the increase in temperature, the volume of the object will also increase.

In the given problem, balloon is inflated almost to its capacity. But on an extremely hot day, it will expand beyond to its capacity due to the thermal expansion.

Therefore, it might be exploded on an extremely warm day.  

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What is the increase in pressure required to decrease volume of mercury by 0.001%
REY [17]

Answer:

Explanation:

Using Boyles law

Boyle's law states that, the volume of a given gas is inversely proportional to it's pressure, provided that temperature is constant

V ∝ 1 / P

V = k / P

VP = k

Then,

V_1 • P_1 = V_2 • P_2

So, if we want an increase in pressure that will decrease volume of mercury by 0.001%

Then, let initial volume be V_1 = V

New volume is V_2 = 0.001% of V

V_2 = 0.00001•V

Let initial pressure be P_1 = P

So,

Using the equation above

V_1•P_1 = V_2•P_2

V × P = 0.00001•V × P_2

Make P_2 subject of formula by dividing be 0.00001•V

P_2 = V × P / 0.00001 × V

Then,

P_2 = 100000 P

So, the new pressure has to be 10^5 times of the old pressure

Now, using bulk modulus

Bulk modulus of mercury=2.8x10¹⁰N/m²

bulk modulus = P/(-∆V/V)

-∆V = 0.001% of V

-∆V = 0.00001•V

-∆V = 10^-5•V

-∆V/V = 10^-5

Them,

Bulk modulus = P / (-∆V/V)

2.8 × 10^10 = P / 10^-5

P = 2.8 × 10^10 × 10^-5

P = 2.8 × 10^5 N/m²

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Explanation:

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Your friends sit in a sled in the snow. If you apply a force pf 75 N to them, they have an acceleration of 0.9 m/s ^ 2. What is
Elza [17]

Answer:

Mass of the sled in the snow 83.33 kg.

<u>Explanation</u>:

Given that,  

Force applied to move the sled in the snow (F) = 75N

\text { Acceleration }(a)=0.9 \mathrm{m} / \mathrm{s}^{2}

We know that

Newton's second law of motion is  

\text { Force }=\text { mass } \times \text { acceleration }

F = ma (Or "force" is equal to "mass" times "acceleration".)

So if we move this around we can isolate mass and get mass

\text { Mass }=\frac{\text { force }}{\text { accelearation }}

\mathrm{M}=\frac{75}{0.9}

M = 83.33 kg

Mass of the sled in the snow <u>83.33 kg.</u>

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Nadya [2.5K]

Answer:

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Lapatulllka [165]

Answer:

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