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3 years ago

Which substance is an example of a colloid?

Chemistry

1 answer:

Semmy [17]3 years ago

8 0

Answer:

Milk would be the only colloid

The sand and water, tomato juice and sugar and water are all known as suspensions (It consists of large particles mixed or suspended in a solution)

Explanation:

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ddd [48]

Its the very last option i believe

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3 years ago

Select the correct answer<br><br> Giving brainliest

Alinara [238K]

Answer:

i also need help with this lmk yo

Explanation:

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3 years ago

Read 2 more answers

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

nikdorinn [45]

Answer : The volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

Explanation :

The balanced chemical reaction will be:

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

First we have to calculate the moles of Al.

$\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}$

Molar mass of Al = 27 g/mole

$\text{Moles of }Al=\frac{55g}{27g/mol}=2mole$

Now we have to calculate the moles of $O_2$ .

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of $O_2$

So, 2 mole of Al react with $\frac{3}{4}\times 2=0.75\times 2$ moles of $O_2$

Now we have to calculate the volume of $O_2$ consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of $O_2$ occupies 22.4 liter volume of $O_2$ gas

So, $0.75\times 2$ mole of $O_2$ occupies $0.75\times 2\times 22.4$ liter volume of $O_2$ gas

Therefore, the volume of $O_2$ consumed are, $0.75\times 2\times 22.4$ L.

3 0

3 years ago

How many elements are identified in tearms of their atoms

lianna [129]

<span>their identified by the number of protons they have in the nucleus which = their electrons. </span>

6 0

4 years ago

Question 9

Shkiper50 [21]

Answer: There are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.

Explanation:

Given: $M_{1}$ = 1.0 M, $V_{1}$ = ?

$M_{2}$ = 0.1 M, $V_{2}$ = 200 mL

Formula used is as follows.

$M_{1}V_{1} = M_{2}V_{2}$

Substitute values into the above formula as follows.

$M_{1}V_{1} = M_{2}V_{2}\\1.0 M \times V_{1} = 0.1 M \times 200 mL\\V_{1} = \frac{0.1 M \times 200 mL}{1.0 M}\\= 20 mL$

Thus, we can conclude that there are 20 milliliters of 1.0 M HCl is required to be diluted to make 200 mL of a 0.1 M solution.

7 0

3 years ago