I dont think with this much amount of information we can solve this...unless its an reversible reaction in that case free energy =0
Answer: Option C - Radical
Explanation:
A radical is a chemical specie carrying a lone electron. In the halogenation of alkanes: take Methane CH4 as the alkane, and Chlorine Cl as the halogen.
The step by step halogenation process is as follows:
CH4 + Cl2 --> CH3• + HCl + Cl•
CH3• + Cl2 --> CH3Cl + HCl
CH3Cl + Cl2 --> CH2Cl2 + HCl + Cl•
CH2Cl2 + Cl2 --> CHCl3 + HCl
CHCl3 + Cl2 --> CCl4 + HCl + Cl•
Chlorine molecule attack methane knocking off an hydrogen atom from it and forming a methyl radical (CH3•), that is subsequently attack by another chlorine molecule. This cycle repeats itself, until no hydrogen atom is available for substitution by the highly reactive chlorine radical.
Note: no cation or anion is formed in the halogenation process
<u>Answer:</u> The concentration of 
ions is 0.10 M and that of 
ions is 0.30 M
<u>Explanation:</u>
We are given:
Concentration of 
= 0.10 M
The chemical equation for the ionization of aluminium bromide follows:
1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions
So, concentration of aluminium ions = 0.10 M
Concentration of bromide ions = ![[(3\times 0.1)]=0.3M](https://tex.z-dn.net/?f=%5B%283%5Ctimes%200.1%29%5D%3D0.3M)
Hence, the concentration of ions is 0.10 M and that of ions is 0.30 M
Answer:
The stable ion the sulfur would form is the sulfide ion,
Explanation:
When any atom accept electrons it converts into negative ion/an anion. So it will change into Z 3− after gaining 3 electrons.
