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vaieri [72.5K]
3 years ago
14

Determine the constant speed at which the cable at A must be drawn in by the motor in order to hoist the load 6 m in 1.5s

Engineering
1 answer:
zlopas [31]3 years ago
5 0

Answer:

4m/s

Explanation:

We know that power supplied by the motor should be equal to the rate at which energy is increased of the mass that is to be hoisted

Mathematically

Power_{motor} } =\frac{Energy }{time}\

We also know that Power = force x velocity      ..................(i)

The force supplied by the motor should be equal to the weight (mg) of the block since we lift the against a force equal to weight of load

=> power = mg x Velocity........(ii)

While hoisting the load at at constant speed only the potential energy of the mass increases

Thus Potential energy = Mass x g x H...................(iii)

where

g = accleration due to gravity (9.81m/s2)

H = Height to which the load is hoisted  

Equating equations (ii) and (iii) we get

m x g x v = \frac{mgh}{t}

thus we get v = H/t

Applying values we get

v = 6/1.5 = 4m/s

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Viefleur [7K]

Answer:

Both come from the sun

Both are reusable sources

and both don't cause pollution

Explanation:

3 0
2 years ago
An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kPa
mote1985 [20]

Answer:

COP = 3.828

W' = 39.18 Kw

Explanation:

From the table A-11 i attached, we can find the entropy for the state 1 at -20°C.

h1 = 238.43 KJ/Kg

s1 = 0.94575 KJ/Kg.K

From table A-12 attached we can do the same for states 3 and 4 but just enthalpy at 800 KPa.

h3 = h4 = hf = 95.47 KJ/Kg

For state 2, we can calculate the enthalpy from table A-13 attached using interpolation at 800 KPa and the condition s2 = s1. We have;

h2 = 275.75 KJ/Kg

The power would be determined from the energy balance in state 1-2 where the mass flow rate will be expressed through the energy balance in state 4-1.

W' = m'(h2 - h1)

W' = Q'_L((h2 - h1)/(h1 - h4))

Where Q'_L = 150 kW

Plugging in the relevant values, we have;

W' = 150((275.75 - 238.43)/(238.43 - 95.47))

W' = 39.18 Kw

Formula foe COP is;

COP = Q'_L/W'

COP = 150/39.18

COP = 3.828

4 0
3 years ago
Which of these materials are insulators? Select the THREE (3) that apply.
lubasha [3.4K]

Answer:

wool, rubber, and plastic

Explanation:

5 0
2 years ago
Describe the refrigeration cycle & how it transfers heat, including all the components & lines. be sure to discuss why t
Amanda [17]

Heat can be diverted away from the area you want to cool using the refrigeration cycle, also known as a heat pump cycle. This is done by repeatedly compressing and expanding the working refrigerant (air, water, synthetic refrigerants, etc.) to change its pressure.

<h3>What is the cycle of a heat pump?</h3>
  • In order to heat the air within a building, a heat pump warms the air outside by drawing heat from it and adding it to it. The following procedure is used to achieve this: A gas is created when liquid refrigerant absorbs heat from the ambient air in the "evaporator."
  • The pressure buildup from the compressor raises the temperature of the refrigerant, just like it does with everything that is put under pressure. The refrigerant is a heated vapor, ranging in temperature from 120° to 140°F, when it exits the compressor.
  • The chemical refrigerant, once transformed from a gas to a liquid state, has a remarkable capacity to absorb heat. The heat inside your house might be absorbed and released outside when the refrigerant undergoes a state shift as a result of compression and pressurization.  

To learn more about Compressor refer to:

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6 0
1 year ago
A particle moves along a circular path of radius 300 mm. If its angular velocity is θ = (2t) rad/s, where t is in seconds, deter
uysha [10]

Answer:

4.83m/s^{2}

Explanation:

For a particle moving in a circular path the resultant  acceleration at any point is the vector sum of radial and the tangential acceleration

Radial acceleration is given by a_{radial}=w^{2}r

Applying values we get  a_{radial}=(2t)^{2}X0.3m

Thus a_{radial}=1.2t^{2}

At time = 2seconds a_{radial}= 4.8m/s^{2}

The tangential acceleration is given by a_{tangential} =\frac{dV}{dt}=\frac{d(wr)}{dt}

a_{tangential}=\frac{d(2tr)}{dt}

a_{tangential}= 2r

a_{tangential}=0.6m/s^{2}

Thus the resultant acceleration is given by

a_{res} =\sqrt{a_{rad}^{2}+a_{tangential}^{2}}

a_{res} =\sqrt{4.8^{2}+0.6^{2}  } =4.83m/s^{2}

8 0
3 years ago
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