The condensed Q formula may be used for operations in which the friction loss can be determined for a: 3, 4, or 5 inch hose.
<h3>What is a firehose friction loss?</h3>
A firehose friction loss can be defined as a measure of the effect of the resistance of water against the inner side of a firehose, which typically results in a pressure drop at the terminal end.
Generally, some of the factors that affect the resistance or friction in a firehose include:
Mathematically, the firehose friction loss can be calculated by using this formula:
FL = C × (Q/100)² × L/100.
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Answer:
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Explanation:
Answer: Attached below is the missing detail and Mohr's circle.
i) б1 = 9.6 Ksi
б2 = -10.7 ksi
ii) 10.2 Ksi
iii) -0.51Ksi
Explanation:
First step :
direct compressive stress on shaft
бd = P / π/4 * d^2
= -20 / 0.785 * 5^2 = -1.09 Ksi
shear stress at the outer surface due to torsion
ζ = 16*T / πd^3
= (16 * 250 ) / π * 5^3 = 010.19 Ksi
<u>Calculate the Principal stress, maximum in-plane shear stress and average normal stress</u>
Using Mohr's circle ( attached below )
<u>i) principal stresses:</u>
б1 = 4.8 cm * 2 = 9.6 Ksi
б2 = -5.35 cm * 2 = -10.7 ksi
<u>ii) maximum in-plane shear stress</u>
ζ = radius of Mohr's circle
= 5.1 cm = 10.2 Ksi ( Given that ; 1 cm = 2Ksi )
<u>iii) average normal stress</u>
= 9.6 + ( - 10.7 ) / 2
= -0.51Ksi
Answer:
displacement power factor is 0.959087
Explanation:
given data
THD = 88%
true power factor = 0.72
solution
we get here total harmonic distribution THD is express as here
THD =
..............1
her g is distortion factor
so put here value and we will get g that is
0.88² =
solve it we get
g = 0.750714
and
displacement power factor is express as
DPF =
.................2
put here value and we will get
DPF =
DPF = 0.959087