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cluponka [151]
1 year ago
12

when discussing valve train components, technician a says stamped rocker arms are very strong and may be used in high-horsepower

engines. technician b says forged rocker arms are used in high-torque, high-horsepower applications. who is correct?
Engineering
1 answer:
mojhsa [17]1 year ago
5 0

From the discussion we know that tehcnician A is the correct statement abaout valve train components. Because of the stamped rocker arms arms are more resistant to more aggressive engine conditions.

<h3>Why stamped rocker arms are very strong for hig-horsepower engines? </h3>

Whether you're dealing mostly with small blocks from a junkyard or a heavily modified race engine, rocker arms play a big role in unleashing horsepower and reducing friction in the valve train. Automotive rocker arms are typically made of stamped steel or aluminum for high speed applications. Some rocker arms (called roller rocker arms) incorporate bearings at the contact points to reduce wear and friction at the contact points. So we know that technician A has correct statement.

Learn more about valve high component: brainly.com/question/28251926

#SPJ4

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Technician A is incorrect so that means Technician B is correct.
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2 years ago
A city emergency management agency and a construction company have formed a public-private partnership. The construction company
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Answer:

B

Explanation:

4 0
2 years ago
To 3 significant digits, what is the temperature of water in degrees C, if its pressure is 350 kPa and the quality is 0.01
liq [111]

Answer:

138.9 °C

Explanation:

The datum of quality is saying to us that liquid water is in equilibrium with steam. Saturated water table gives information about this liquid-vapour equilibrium. In figure attached, it can be seen that at 350 kPa of pressure (or 3.5 bar) equilibrium temperature is 138.9 °C

3 0
2 years ago
The temperature of a system rises by 10 °C during a heating process. Express the rise in temperature of K, R, and °F.
Lorico [155]

Explanation:

Given T = 10 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (10 + 273.15) K = 283.15 K

<u>T = 283.15 K </u>

The conversion of T( °C) to T(F) is shown below:

T (°F) = (T (°C) × 9/5) + 32  

So,

T (°F) = (10 × 9/5) + 32 = 50 °F

<u>T = 50 °F</u>

The conversion of T( °C) to T(R) is shown below:

T (R) = (T (°C) × 9/5) + 491.67

So,

T (R) = (10 × 9/5) + 491.67 = 509.67 R

<u>T = 509.67 R</u>

6 0
3 years ago
When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note th
Amanda [17]

Answer:

The answer is "2 m/s".

Explanation:

The triangle from of the right angle:

\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant

Differentiating the above equation:

\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\

\to V_A=  \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\

        = \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}

3 0
2 years ago
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