1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cluponka [151]
1 year ago
12

when discussing valve train components, technician a says stamped rocker arms are very strong and may be used in high-horsepower

engines. technician b says forged rocker arms are used in high-torque, high-horsepower applications. who is correct?
Engineering
1 answer:
mojhsa [17]1 year ago
5 0

From the discussion we know that tehcnician A is the correct statement abaout valve train components. Because of the stamped rocker arms arms are more resistant to more aggressive engine conditions.

<h3>Why stamped rocker arms are very strong for hig-horsepower engines? </h3>

Whether you're dealing mostly with small blocks from a junkyard or a heavily modified race engine, rocker arms play a big role in unleashing horsepower and reducing friction in the valve train. Automotive rocker arms are typically made of stamped steel or aluminum for high speed applications. Some rocker arms (called roller rocker arms) incorporate bearings at the contact points to reduce wear and friction at the contact points. So we know that technician A has correct statement.

Learn more about valve high component: brainly.com/question/28251926

#SPJ4

You might be interested in
Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ
deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u />a=2r

Now,

The unit cell volume will be:

=a^3

=(2r)^3

=8r^3

At one atom per cell, atom volume will be:

=(1)\times (\frac{4 \pi r^3}{3})

Then the ratio will be:

Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent

        =52.4 \ percent

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

d=8r=a\sqrt{3}

       a=\frac{8}{\sqrt{3}}r

The unit cell volume will be:

=a^1

=(\frac{8r}{\sqrt{3}})^1

At eight atom per cell, the atom volume will be:

=8(\frac{4 \pi r^1}{3})

Then the Ratio will be:

Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent

        =34 \ percent

Note: percent = %

5 0
3 years ago
The point in an electrical circuit that is connected to the negative side of a power supply is called what?
Anna11 [10]

Answer: will you have to do it on your own first

Explanation:

7 0
3 years ago
A STANDARDIZED RECIPE WILL ALWAYS MAKE A CONSISTENT quality AND CONSISTENT
Zielflug [23.3K]

Answer:

Quantity.

Explanation:

A standardized prescription is one that contains generic prescriptions indicated for a certain disease, that is, one that contains the basic treatments indicated for it, including drugs and treatments prescribed in uniform quantities and qualities for all patients. Thus, these recipes do not aim at the individual characteristics of the patient, but at the general characteristics of the diagnosed disease and its main treatments.

7 0
3 years ago
Assume that a surface-grinding operation is being carried out under the following conditions: D = 250 mm, d 0.1 mm, ys 0.5 m/s a
Misha Larkins [42]

Answer:

modify temperature is lower than by the 0.196 %

Explanation:

given data

D = 250 mm

d = 0.1 mm

v = 0.5 m/s

V = 50 m/s

D = 150 mm

d = 0.1 mm

v = 0.3 m/s

V = 25 m/s

solution

first we get here initial coating condition for temperature change ΔT is

ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2}    ...............1

put here value for both condition

ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}  

ΔT = 7.07 A      ......................2

and

ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}  

ΔT = 5.68 A       .......................3

so here percentage change is

percentage change = \frac{5.68 A-7.07 A }{7.07 A }  

percentage change  = - 0.196

so that modify temperature is lower than by the 0.196 %

5 0
3 years ago
Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2
motikmotik

Answer:

The answer is "112.97 \ \frac{ft}{s}"

Explanation:

Air flowing into thep_1 = 20 \ \frac{lbf}{in^2}

Flow rate of the mass m  = 230.556 \frac{lbm}{s}

inlet temperature T_1 = 700^{\circ} F

PipelineA= 5 \times 4 \ ft

Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:

\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}

      = \frac{\frac{1545}{28.97}(70^{\circ}F+459.67)}{20} \times \frac{1}{144}\\\\=9.8 \frac{ft3}{lb}

V= \frac{mv}{A}

   = \frac{230.556 \frac{lbm}{s} \times 9.8 \frac{ft^3}{lb}}{5 \times 4 \ ft^2}\\\\= 112.97 \frac{ft}{s}

8 0
3 years ago
Other questions:
  • Next → Fluid Systems: Mastery Test Select the correct answer from each drop-down menu. What type of systems are used in the Indu
    14·1 answer
  • The cart travels the track again and now experiences a constant tangential acceleration from point A to point C. The speeds of t
    13·1 answer
  • Name their temperaments:
    14·1 answer
  • Find two quotes from the text that relate to bravery of odssey. Cite the quote with the Book number and line number. Add two sen
    13·1 answer
  • Consider an ideal gas undergoing a constant pressure process from state 1 to state
    12·1 answer
  • X²-12x=0 ПЖ срочно реально решите помагие ​
    9·1 answer
  • What is "Engineering"?
    12·1 answer
  • Someone please help me and explain this in detail!!!!!
    9·1 answer
  • Type the correct answer in the box. Spell all words correctly.
    13·1 answer
  • 6.03 Discussion: Then &amp; Now - Safety
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!