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Y_Kistochka [10]

3 years ago

12

In a hexagonal-close-pack (hcp) unit cell, the ratio of lattice points to octahedral holes to tetrahedral holes is 1:1:2. What i

s the general formula for a compound if anions occupy the hcp lattice points and cations occupy half of the tetrahedral holes? AB A3B AB2 A2B What is the general formula for a compound if anions occupy the hcp lattice points and cations occupy all the tetrahedral holes? AB A2B AB2 A3B

1 answer:

Alex777 [14]3 years ago

6 0

Explanation:

In a hexagonal-close-pack (HCP) unit cell, the ratio of lattice points to octahedral holes to tetrahedral holes = 1 : 1 : 2

let the :

Number of lattice point = 1x.

Number of octahedral points = 1x

Number of tetrahedral points = 2x

If anions occupy the HCP lattice points and cations occupy half of the tetrahedral holes.

Number of anions occupying the HCP lattice points, A= 1x

Number of cations occupying the tetrahedral points, B = $\frac{2x}{2}=x$

The formula of the compound will be = $A_{1x}B_{1x}=AB$

If anions occupy the HCP lattice points and cations occupy all of the tetrahedral holes.

Number of anions occupying the HCP lattice points, A= 1x

Number of cations occupying the tetrahedral points, B = 2x

The formula of the compound will be = $A_{1x}B_{2x}=AB_2$

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2 years ago

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Now that we have the moles, we know that the metal and the hydrogen has a mole ratio of 1:1 according to the reaction, so, this means that:

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8 0

3 years ago

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