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2 years ago

14

A higher amplitude means...?

1 answer:

vekshin12 years ago

4 0

Answer:

High amplitude is equivalent to loud sounds.

Explanation:

Larger the amplitude, the higher the energy. In sound, amplitude refers to the magnitude of compression and expansion experienced by the medium the sound wave is travelling through. This amplitude is perceived by our ears as loudness.

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D. Explain why hydrogen produces three light in spectrometer

horrorfan [7]

Answer:

Though a hydrogen atom has only one electron, it contains a large number of shells, so when this single electron jumps from one shell to another, a photon is emitted, and the energy difference of the shells causes different wavelengths to be released. Hence, mono-electronic hydrogen has many spectral lines.

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8 0

3 years ago

The density of human blood is 1.06g/ml the volume is 5.5l what is the mass in kg

kondor19780726 [428]

The mass of the blood is 5.8 kg.

<em>V</em> = 5.5 L = 5500 mL

Mass = 5500 mL × (1.06 g/1 mL) = 5800 g = 5.8 kg

6 0

3 years ago

Help please thank you!!!

omeli [17]

Answer:

I think its J

Explanation:

sorry if im wrong

7 0

2 years ago

Read 2 more answers

How many grams are there in a 14.5 moles lithium permanganate

frutty [35]

There are 1825.6 g in a 14.5 moles Lithium permanganate

<h3> Further explanation</h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass :

$\tt mol=\dfrac{mass}{MW}$

moles of Lithium permanganate = 14.5

Lithium permanganate (LiMnO4) MW=125.9 g/mol, so mass :

$\tt mass=mol\times MW\\\\mass=14.5\times 125.9~g/mol\\\\mass=1825.6~g$

5 0

3 years ago

blondinia [14]

Answer:

$[CO]=[Cl_2]=0.01436M$

$[COCl_2]=0.00064M$

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

$K=\frac{[CO][Cl_2]}{[COCl_2]}$

Which can be written in terms of x, according to the ICE table:

$0.32=\frac{x^2}{0.015M-x}$

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

$[CO]=[Cl_2]=0.01436M$

$[COCl_2]=0.015M-0.01436M=0.00064M$

Regards!

5 0

3 years ago