The car's mass is 1600 kg.
Its weight is (mass) x (gravity).
On Earth, that's (1600 kg) x (9.8 m/s²) = 15,680 Newtons.
At the moment, that's the only force acting on the car, directed downward and provided by gravity.
If you want to lift the car, then the net force has to be directed upward, and must either exactly cancel or exceed the force of gravity.
So the minimum force required to lift the car is <em>15,680 Newtons</em>, directed vertically upward.
The atomic number is the number of protons. So, you can subtract the atomic number from the mass number to find the number of neutrons.
I hope this helps! :)
Answer:
197.76 m
Explanation:
r = Radius of the path = 20.6 km = 
= The angle subtended by moon = 
Distance traveled is given by
The distance traveled by the jet is 197.76 m
<h3><u>Answer;</u></h3>
volume = 6.3 × 10^-2 L
<h3><u>Explanation</u>;</h3>
Volume = mass/density
Mass = 0.0565 Kg,
Density = 900 kg/m³
= 0.0565 kg/ 900 kg /m³
= 6.3 × 10^-5 M³
but; 1000 L = 1 m³
Hence, <u>volume = 6.3 × 10^-2 L</u>
According to the <u>Third Kepler’s Law of Planetary motion</u> “<em>The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>
In other words, this law states a relation between the orbital period 
of a body (moon, planet, satellite) orbiting a greater body in space with the size 
of its orbit.
This Law is originally expressed as follows:
<h2>
(1)
</h2>
Where;
is the Gravitational Constant and its value is 
is the mass of Jupiter
is the semimajor axis of the orbit Io describes around Jupiter (assuming it is a circular orbit, the semimajor axis is equal to the radius of the orbit)
If we want to find the period, we have to express equation (1) as written below and substitute all the values:
<h2>
(2)
</h2>
Then:
<h2>
(3)
</h2>
Which is the same as:
<h2>
</h2>
Therefore, the answer is:
The orbital period of Io is 42.482 h
