Answer:
A. Zero
Explanation:
Given data,
The charge of the test charge, q = 1 C
The distance the charge moved against the filed of intensity, x = 30 cm
= 0.3 m
The electric field intensity, E = 50 N/C
The energy stored in the charge at 0.3 m is given by the formula,
V = k q/r
Where,
= 9 x 10⁹ Nm²C⁻²
The charge is moved from the potential V₁ to V₂ at 30 cm
Substituting the given values in the above equation
V₁ = 9 x 10⁹ x 30 / 0.3
= 1.5 x 10¹² J
And,
V₂ = 1.5 x 10¹² J
The energy stored in it is,
W = V₂ - V₁
= 0
Hence, the energy stored in the charge is, W = 0
Linear Scientific Process
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From the question we are told that
The initial pressure of the gas is
The volume of the second bulb is
The final pressure of the gas is
Let the unknown volume be represented as
Generally from Boyle's law we have that
=>
=>
Yes, for balance.hope this helped.
Answer:
(a) 0.81 V
(b) 0.52 V
Explanation:
Number of turns, N = 150
Radius, r = 2.5 cm = 0.025 m
Magnetic field, B = 0.060 T
f = 440 rev/min = 440 / 60 = 7.33 rps
A.
The maximum emf is given by
e = N x B x A x 2 x π x f
e = 150 x 0.060 x 3.14 x 0.025 x 0.025 x 2 x 3.14 x 7.33
e = 0.81 V
B.
The back emf is given by
e' = 2e / π = 2 x 0.81 / 3.14 = 0.52 V