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dsp73
3 years ago
7

12.7 cm =_____________mm ​

Physics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
Answer : 12.7 cm = 127. mm
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Beams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. A certain gun has an elec
Natasha2012 [34]

Answer: v = 2.75 * 10^7 m/s

Explanation: Since the electric field is a uniform one and the distance is small, the motion of the electron is of a constant acceleration, hence newton's laws of motion is applicable.

From the question

E=strength of electric field = 214N/c

q=magnitude of an electronic charge = 1.609* 10^-16c

m= mass of an electronic charge = 9.11*10^-31kg

v = velocity of electron.

S= distance covered = 1cm = 0.01m

a = acceleration of electron.

F = ma but F=Eq

Eq = ma.

a = Eq/m

a = 214 * 1.609*10^-16/ 9.11 * 10^-31

a = 344.32 * 10^-16/ 9.11 * 10 ^-31

a = 3. 779* 10^16 m/s²

Before the electron is accelerated, they are always not moving, hence initial velocity (u) = 0.

By using the equation of motion, we have

v² = u² + 2aS

But u = 0

v² = 2aS

v²= 2* 3.779*10^16 * 0.01

v² = 7.558 * 10^14

v = √7.558 * 10^14

v = 2.75 * 10^7 m/s.

6 0
3 years ago
x rays with wavelength of 2.0nm scatter from a nacl crystal with plane spacing 0.281 nm find the scattering
ValentinkaMS [17]

Explanation:

It is given that,

Wavelength of x-rays = 2 nm

Plane spacing, d = 0.281 nm

It is assumed to find the scattering angle for second order maxima.

For 2nd order, Bragg's law is given by :

2d\sin\theta=n\lambda

For second order, n = 2

\sin\theta=\dfrac{n\lambda}{2d}\\\\\sin\theta=\dfrac{2\times 2\ nm}{2\times 0.28\ nm}\\\\\theta=\sin^{-1}(7.14)

Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.

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3 years ago
Imagine you are charged to manage a project that aims to install wireless access points (aps) throughout the university campus.
Vitek1552 [10]

If you are charged to manage a project that aims to install wireless access points (aps) throughout the university campus, the steps to a foolproof plan for this project would be -

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The most crucial step in any WiFi installation is probably knowing what your network needs are.

2. Select the appropriate hardware for your wireless network

Finding the ideal access point is much simpler if your needs are clear, but the wide range of options might be difficult.

3. Recognize your devices’ network restrictions.

It’s crucial to keep in mind that other factors besides your Internet connection and network hardware might affect how well your network performs.

4. Take into account the various cables you’ll need to use.

5. Consider how nearby interference may affect the installation of your wireless access point.

6. Decide where to put your wireless access point.

7. Analyze signal strength prior to making a decision.

To know more about access points (aps) visit:

brainly.com/question/14231305

#SPJ4

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1 year ago
A sample of a gaseous substance changes into a liquid
Leviafan [203]

dry ice is one example of this.

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3 years ago
How many total atoms are in one molecule of nickel hydroxide, Ni(OH)2?
Nataly [62]
<span>so I'm pretty sure that the answer is 92.70808 g/mol</span>
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3 years ago
Read 2 more answers
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