All categories

4 years ago

12.7 cm =_____________mm

Physics

1 answer:

BlackZzzverrR [31]4 years ago

4 0

Answer : 12.7 cm = 127. mm

You might be interested in

Motion is a change in ____.

Nonamiya [84]

Answer:

Position

Explanation:

Motion is a change in position.

4 0

4 years ago

Do you add the initial position and final position to get distance?

mamaluj [8]

You can do d=st (s is speed and t is time) or you can use pythagorean theorem if the distance is or the two positions is a right angle.

4 0

3 years ago

Plz answer #2 plz this is 8th grade science / physics

MrRissso [65]

All you need is your science book

5 0

3 years ago

What is the difference between weathering, erosion, and decomposition?

ladessa [460]

Weathering is where something is changed or mutilated by the weather. Erosion is hwere water or an other substance digs awaya at something and wears it out. I don't exactly know the last one or how to explain

8 0

4 years ago

Read 2 more answers

The height of a typical playground slide is about 1.8 m and it rises at an angle of 30 ∘ above the horizontal.

Salsk061 [2.6K]

Answer:

$5.94\ \text{m/s}$

$1.7$

$0.577$

Explanation:

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

$\theta$ = Angle of slope = $30^{\circ}$

v = Velocity of child at the bottom of the slide

$\mu_k$ = Coefficient of kinetic friction

$\mu_s$ = Coefficient of static friction

h = Height of slope = 1.8 m

The energy balance of the system is given by

$mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.8}\\\Rightarrow v=5.94\ \text{m/s}$

The speed of the child at the bottom of the slide is $5.94\ \text{m/s}$

Length of the slide is given by

$l=h\sin\theta\\\Rightarrow l=1.8\sin30^{\circ}\\\Rightarrow l=0.9\ \text{m}$

$v=\dfrac{1}{2}\times5.94\\\Rightarrow v=2.97\ \text{m/s}$

The force energy balance of the system is given by

$mgh=\dfrac{1}{2}mv^2+\mu_kmg\cos\theta l\\\Rightarrow \mu_k=\dfrac{gh-\dfrac{1}{2}v^2}{gl\cos\theta}\\\Rightarrow \mu_k=\dfrac{9.81\times 1.8-\dfrac{1}{2}\times 2.97^2}{9.81\times 0.9\cos30^{\circ}}\\\Rightarrow \mu_k=1.73$

The coefficient of kinetic friction is $1.7$ .

For static friction

$\mu_s\geq\tan30^{\circ}\\\Rightarrow \mu_s\geq0.577$

So, the minimum possible value for the coefficient of static friction is $0.577$ .

8 0

3 years ago

12.7 cm =_____________mm ​

12.7 cm =_____________mm