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dsp73
3 years ago
7

12.7 cm =_____________mm ​

Physics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
Answer : 12.7 cm = 127. mm
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At a certain time a particle had a speed of 87 m/s in the positive x direction, and 6.0 s later its speed was 74 m/s in the oppo
Viefleur [7K]

Answer:

The average acceleration during the 6.0 s interval was -27 m/s².

Explanation:

Hi there!

The average acceleration is defined as the change in velocity over time:

a = Δv/t

Where:

a = acceleration.

Δv = change in velocity = final velocity - initial velocity

t = elapsed time

The change in velocity will be:

Δv = final velocity - initial velocity

Δv = -74 m/s - 87 m/s = -161 m/s

(notice the negative sign of the velocity that is in opposite direction to the direction considered positive)

Then the average acceleration will be:

a = Δv/t

a = -161 m/s / 6.0 s

a = -27 m/s²

The average acceleration during the 6.0 s interval was -27 m/s².

8 0
3 years ago
A glass of root beer with a scoop of ice cream floating on top and a straw sticking out.
vampirchik [111]

Answer:

These forces are all equal and cancel each other out. Gravity pushes downward on the ice cream. This can also be called the weight of the ice cream. Buoyant force pushes the ice cream upward

6 0
2 years ago
The capacitor is now reconnected to the battery, and the plate separation is restored to d. A dielectric plate is slowly moved i
Paha777 [63]

Answer:

U2 = KAε0V2 / (2d)

Explanation:

The dielectric constant K just replaces the "3″ from Part B.

8 0
3 years ago
A toroid having a square cross section, 5.49 cm on a side, and an inner radius of 18.1 cm has 450 turns and carries a current of
joja [24]

Answer:

(a) 4.27 x 10^-4 Telsa

(b) 3.28 x 10^-4 Telsa

Explanation:

side of square, a = 5.49 cm

inner radius, r = 18.1 cm = 0.181 m

number of turns,N = 450

current, i = 0.859 A

(a)

The magnetic field due to a solenoid due to inner radius is

B = \frac{\mu_{0}Ni}{2\pi r_{inner}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.181}

B = 4.27 x 10^-4 Telsa

(b)

The outer radius is R = 18.1 + 5.49 = 23.59 cm = 0.236 m

The magnetic field due to the outer radius is

B = \frac{\mu_{0}Ni}{2\pi r_{outer}}

B = \frac{4\pi\times 10^{-7}\times 450\times 0.859}{2\pi \times 0.236}

B = 3.28 x 10^-4 Tesla

7 0
3 years ago
What is the acceleration of a 59 kg object pushed with a force of 500 Newton's ?
Igoryamba

Answer:

a=500/50=10 m/s^2

Explanation:

f=m•a     a=f/m

a=500/50= 10 m/s^2

4 0
2 years ago
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