given that snow is projected at an angle of 40 degree
It range is given as a = 19 ft
now we can use the formula of horizontal range
<u>so its initial speed must be 7.6 m/s</u>
C2H5OH (l) + 3 O2 (g) = 2 CO2 (g)+ 3 H2O (l/g)
Answer
given,
v = 128 ft/s
angle made with horizontal = 30°
now,
horizontal component of velocity
vx = v cos θ = 128 x cos 30° = 110.85 ft/s
vertical component of velocity
vy = v sin θ = 128 x sin 30° = 64 m/s
time taken to strike the ground
using equation of motion
v = u + at
0 =-64 -32 x t
t = 2 s
total time of flight is equal to
T = 2 t = 2 x 2 = 4 s
b) maximum height
using equation of motion
v² = u² + 2 a h
0 = 64² - 2 x 32 x h
64 h = 64²
h = 64 ft
c) range
R = v_x × time of flight
R = 110.85 × 4
R = 443.4 ft
Answer:
Momentum of red car = 5kgm/s
Momentum of blue car = 0kgm/s
Explanation:
Momentum = mass × velocity
For the red car
Mass = 1kg
Velocity = 5m/s
Momentum of the red car = 1kg × 5m/s
Momentum of the red car = 5kgm/s
For the blue car.
Mass = 1kg
Velocity = 0m/s(shows that the blue car is stationery)
Momentum = 1kg ×0m/s
Momentum of the blue car = 0kgm/s
