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andre [41]
3 years ago
14

if you were in a car that drove off the edge of a cliff, why would you be momentarily weightless? would gravity still be acting

on you?
Physics
1 answer:
Andrews [41]3 years ago
3 0

Answer: Gravity will be on you since you are falling. For instance if you where skydiving you are free falling which will be similar to the car. Therefore gravity does play a role because whatever goes up must come down.

Explanation:

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A wire is wrapped around a piece of iron, and then electricity is run through the wire. What happens to the iron?
katrin [286]
Search Results<span>By simply wrapping wire that has an electrical current running through it around a nail, you can make an electromagnet. When the electric current moves through a wire, it makes a magnetic field. ... You can make a temporary magnet by stroking apiece of iron or steel (such as a needle) along with a permanent magnet.

Hope This Helps!</span>
7 0
3 years ago
When a wire within a closed circuit is coiled upon a nail, the nail will _______.
Natali5045456 [20]

when wire is coiled upon a nail then it will posses magnetic characteristics

This is due to the coiled shape it will behave like a solenoid and the magnetic field of solenoid is given as

B = \mu_o ni

so here when wire is coiled up on a nail then due to the magnetic field of the coil the nail will attain magnetic characteristic.

so correct answer will be

<em>Possess magnetic properties </em>

5 0
3 years ago
Read 2 more answers
Please. Physics is so difficult.
Softa [21]

Answer:

0.010 m

Explanation:

So the equation for a pendulum period is: y=2\pi\sqrt{\frac{L}{g}} where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:

1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\

Evaluate the multiplication in front

1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}

Divide both sides by 6.28

0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}

Square both sides

0.100 s^2= \frac{L}{9.8 m\backslash s^2}

Multiply both sides by m/s^2  (the s^2 will cancel out)

0.984 m = L

Now now let's find the length when it's two seconds

2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}

Divide both sides by 6.28

0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}

Square both sides

0.101 s^2 = \frac{L}{9.8 m\backslash s^2}

Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)

0.994 m = L

So to find the difference you simply subtract

0.984 - 0.994 = 0.010 m

4 0
1 year ago
Read 2 more answers
Rebecca heated 50mL of water from 0 degrees Celsius to 60 degrees Celsius. How much energy did she use to heat the water? Rememb
kramer

Answer:

12552 J or 3000 calories

Explanation:

Q = m × c × ∆T

Where;

Q = amount of heat energy (J)

m = mass of water (g)

c = specific heat capacity (4.184 J/g°C)

∆T = change in temperature

For 50mL of water, there are 50g, hence, m = 50g, c = 4.184 J/g°C, initial temperature = 0°C, final temperature = 60°C.

Q = m × c × ∆T

Q = 50 × 4.184 × (60 - 0)

Q = 209.2 × 60

Q = 12552 J

Hence, the amount of heat energy used to heat the water is 12552 J or 3000 calories

3 0
3 years ago
The membrane that surrounds a certain type of living cell has a surface area of 7.1 x 10-9 m2 and a thickness of 1.5 x 10-8 m. A
hoa [83]

Answer:

Q = +1.4 pC

Explanation:

  • The capacitance of any capacitor, by definition, is as follows:
  •  C = \frac{Q}{V} (1)
  • Applying Gauss'Law and the definition of electric potential, it can be showed that the capacitance of a parallel-plate capacitor can be expressed as follows:
  •  C = \frac{\epsilon_{r}*\epsilon_{0} * A}{d} (2)
  • Where εr is the dielectric constant of the material that fills the space between the plates, A is the area of one of the plates, and d, is the separation between them.
  • Replacing by the givens in (2) we can find the value of the capacitance C, as follows:

       C = \frac{\ 4.4*8.85e-12C2/N*m2*7.1e-9m2}{1.5e-8m} = 18.4e-12 F = 18.4 pF

  • Replacing the values of C and V in (1), we can solve for Q, as follows:

       Q = C*V = 18.4e-12 F* 75.9e-3 V = 1.4e-12 C = +1.4 pC

  • As the outer surface is at a higher potential that the inside surface, the charge on it must be positive, and is equal to +1.4 pC.
7 0
3 years ago
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