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Sonja [21]
4 years ago
9

. Why must the cyclist accelerate before reaching the hillock?

Physics
1 answer:
babunello [35]4 years ago
3 0

Short answer:

So that the cyclist does not slide back down

 

Long answer:

<span>The main forces a cyclist must conquer are air resistance and gravity. Air resistance increases exponentially with speed. In the switch from cycling on a flat road to hiking a hill, the decreased speed reduces air resistance to the point where drafting other riders offers small benefit. At this point, smaller cyclists, who have finer power-to-weight ratios, will be able to break away from the peloton. Climbing skill can be improved by minimizing weight, and also by pedalling at a constantly elevated rhythm. Large cyclists can attain greater downhill speeds, but on mountainous courses smaller cyclists still have a benefit. </span>

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Tju [1.3M]

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4 0
3 years ago
A) The motor speed is less than wheel speed.
n200080 [17]

For the following statements

A) The motor speed is less than wheel speed.

B) The output power of the motor is positive during hill climbing.

C) The wheel torque is more than motor torque

These assertions are given respectively as

  • false
  • true
  • false
<h3>What are speed, power, and Torque?</h3>

Speed: defined as the ratio of operation with respect to distance and time

Power: defined as the ability to work

Torque: This is the speed of a rotating object

Generally, the equation for Speed, Power, Torque  is mathematically given as

V=m/s

P=w/t

T=rfsin\theta

In conclusion

For a moving car, the wheels speed is in equilibrium with the motor speed Hence false

The output power during a hill climb is positive cause work is been done, Hence true

The wheel torque also is in equilibrium with the motor Torque, Hence false

Read more about Work

brainly.com/question/756198

5 0
3 years ago
20 POINTS!!!
hram777 [196]
I think its inductance. If its not then I think its none of the above
5 0
3 years ago
A cylindrical shell of radius 7.00 cm and length 2.21 m has its charge uniformly distributed on its curved surface. The magnitud
polet [3.4K]

Answer:

The net charge on the shell is 30x10^-9C

Explanation:

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8 0
4 years ago
Consider a basketball player spinning a ball on the tip of a finger. If a player performs 1.99 J of work to set the ball spinnin
scoundrel [369]

To solve this problem it is necessary to apply the concepts related to rotational kinetic energy, the definition of the moment of inertia for a sphere and the obtaining of the radius through the circumference. Mathematically kinetic energy can be given as:

KE= I\omega^2

Where,

I = Moment of inertia

\omega = Angular velocity

According to the information given we have that the radius is

\Phi= 2\pi r

0.749m = 2\pi r

r = 0.1192m

With the radius obtained we can calculate the moment of inertia which is

I = \frac{2}{3}mr^2

I = \frac{2}{3}(0.624)(0.1192)^2

I = 5.91*10^{-3} kg \cdot m^2

Finally, from the energy equation and rearranging the expression to obtain the angular velocity we have to

\omega = \sqrt{\frac{2KE}{I}}

\omega = \sqrt{\frac{2(1.99)}{5.91*10^{-3}}}

\omega = 25.95rad/s

Therefore the angular speed will the ball rotate is 25.95rad/s

8 0
3 years ago
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