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zepelin [54]
3 years ago
7

You're driving in a car at 50 km/h and bump into a car ahead traveling at 48 km/h in the same direction. the speed of impact is

Physics
1 answer:
salantis [7]3 years ago
6 0

To solve this problem, we must remember about the law of conservation of momentum. The initial momentum mist be equal to the final momentum, that is:

m1 v1 + m2 v2 = (m1 + m2) v’

where v’ is the speed of impact

Since we are not given the masses of each car m1 and m2, so let us assume that they are equal, such that:

m1 = m2 = m

Which makes the equation:

m v1 + m v2 = (2 m) v’

Cancelling m and substituting the v values:

50 + 48 = 2 v’

2 v’ = 98

v ‘ = 49 km/h

 

<span>The speed of impact is 49 km/h.</span>

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For every action there is an equal and opposite reaction. What does this phrase mean in Physics?
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Answer:

Explanation:

The Term "For every action, there is an equal and opposite reaction" is derived from Newton's third law of motion.

This can be explained by an example of a block placed on the flat surface.

The weight of the block applies an action force on the surface while Surface applies a reaction force on the block. Action and reaction force applies to different bodies other would have canceled each other. Action and reaction forces are always acting in pairs. The magnitude of reaction force depends upon the action forces as both of them are equal in magnitude but opposite in direction.  

7 0
3 years ago
The sound level at 1.0 m from a certain talking person talking is 60 dB. You are surrounded by five such people, all 1.0 m from
Hunter-Best [27]

Answer:

66.98 db

Explanation:

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2 years ago
A rocket moves upward, starting from rest with an acceleration of +30.0 m/s2 for 5.00 s. It runs out of fuel at the end of this
olchik [2.2K]

Answer:

The distance covered by the rocket after fuel ran out is 3442.04 m

Explanation:

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time t=5 s

Since the rocket starts from rest initial velocity  u=0 s

The distance it travelled within this time is given by  s=ut+ \frac{1}{2} at^2                                                                                                  =0 \times 5+ \frac{1}{2} (30\times25)=375 m

Velocity at this point is given by v=u+at

v=0+30\times5=150m/s

Given that at this height it runs out of fuel but travels further. Here final velocity v=0(maximum height), initial velocityu=150 m/s  and time to zero velocity t=\frac{v}{g} = \frac{150}{9.8} =15.3 s.

Thus it travels 15.3 seconds more after fuel running out. The distance covered during this period is given

s= ut+\frac{1}{2} gt^2=150 \times 15.3+1/2 \times9.8 \times 15.3^2=3442.04 m

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2 years ago
While drag racing out of the parking lot I timed myself at a speed of
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Answer:

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Explanation:

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3 years ago
To practice tactics box 13.1 hydrostatics. in problems about liquids in hydrostatic equilibrium, you often need to find the pres
OLEGan [10]

Answer:

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