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2 years ago

8

Anthony is deciding between different savings accounts at his bank. He has four options, based on how frequently interest compou

nds. Which should he choose if he wants the best rate of return on his interest?

1 answer:

77julia77 [94]2 years ago

5 0

So annual compounding means that the account is compound once a year, semi-annual is 2 times a year, monthly compounded is every month (so 12 times a year). and daily is every day (so 365 times a year). If he wants the best rate of return on his interest, or the most money, he should choose daily compounding because his funds are being compounded every day.

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The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum

kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20×10^{-2}\ \mu F$ .

We need to calculate the resonance frequency

Using formula of frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.88\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi\times f\times C\times V_{c}$

$I=2\pi\times2356.88\times1.20\times10^{-8}\times590$

$I=0.1048\ A$

Impedance of the circuit is

$z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}$

At resonance frequency $X_{L}=X_{C}$

$Z=R$

We need to calculate the maximum voltage

Using ohm's law

$V=I\times R$

$V=0.1048\times400$

$V=41.92\ V$

Hence, The maximum voltage is 41.92 V.

4 0

2 years ago

Calculate the mass number of an atom with 8 protons, 12 neutrons and 10 electrons

Radda [10]

Answer: 20

Explanation: Mass number is the number of neutrons plus the number of protons. 8 + 12 gives 20.

7 0

3 years ago

A sharp raises a note by

vivado [14]

The answer should be B. A half step

8 0

3 years ago

Read 2 more answers

If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing orange-yellow. The light is emitte

Alona [7]

Answer:

2.11eV

Explanation:

We know that speed of light is it's wavelength times frequency.

$\therefore f=v/\lambda\\=(3\times10^8m/s)/(589mm\times1m/1\times 10^9nm)\\=5.09\times10^1^4s^-1 \ or \ 5.09\times10^1^4Hz$

Planck's constant is $6.626\times 10^3^4Js$

The energy gap is calculated by multyplying the light's frequency by planck's constant:

$E_c=5.09\times10^1^4s^-^1\times 6.626\times10^-^3^4Js\\\\=3.37\times 10^-^1^9J \ \ \ \ \ \ #1eV=1.06\times 10^-^1^9J\\\\=2.11eV$

Hence, the energy gap is 2.11eV

4 0

3 years ago

How do you solve <img src="https://tex.z-dn.net/?f=4x%5E%7B3%7D" id="TexFormula1" title="4x^{3}" alt="4x^{3}" align="absmiddle"

Vlad1618 [11]

$Hello$ $There!$

Here's a explanation!

Let's solve your equation step-by-step.

$4x^3=2x^-^1$

$4x^3=\frac{2}{x}$

Step 1: Multiply both sides by x.

$4x^4=2$

$\frac{4x^4}{4} =\frac{2}{4}$

(Divide both sides by 4).

$x^4=\frac{1}{2}$

$x=+(\frac{1}{2} )^(^\frac{1}{4} ^)$

Take the root.

ANSWER!

$x=0.840896$ $Or$ $x=-0.840896$

Hopefully, this helps you!!

$AnimeVines$

8 0

3 years ago