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Masja [62]
3 years ago
8

Anthony is deciding between different savings accounts at his bank. He has four options, based on how frequently interest compou

nds. Which should he choose if he wants the best rate of return on his interest?
Physics
1 answer:
77julia77 [94]3 years ago
5 0
So annual compounding means that the account is compound once a year, semi-annual is 2 times a year, monthly compounded is every month (so 12 times a year). and daily is every day (so 365 times a year). If he wants the best rate of return on his interest, or the most money, he should choose daily compounding because his funds are being compounded every day. 
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A 1200 kg car accelerats from reat to 10.0 m/s in a time of 4.50 seconds. Calculate the force that thr car's tires exerted on th
Aleksandr [31]

Answer:

2667 N

Explanation:

<h2>Method 1: Impulse </h2>

We can solve this problem by using the impulse formula.

  • FΔt = mΔv  
  • Δt = time interval, m = mass of the car (kg), Δv = change in velocity

We have three known variables, so we can solve for the fourth: F.

Divide Δt from both sides to isolate F.

  • F = (mΔv)/Δt  

Substitute known values into the equation.

  • F = [(1200 kg)(10 m/s -  0 m/s)] / 4.5 s
  • F = [(1200)(10)]/4.5
  • F = 12000/4.5
  • F = 2666.666667 N

The force that the car's tires exert on the road is 2667 N.

<h2>Method 2: Newton's Second Law</h2>

The force that the car's tires exert on the road is equivalent to the force that the road exerts on the car due to Newton's Third Law of Motion.

We can calculate the force that the car's tires exert on the road by using the formula F = ma, which was derived from Newton's Second Law of Motion.

  • F = ma
  • F = force exerted on the car, m = mass of the car (kg), a = acceleration of the car (m/s²)

We are given the mass of the car, velocity of the car, and the time in which it accelerated.

We can use this equation for acceleration:

  • a = Δv/Δt
  • Δv = final velocity - initial velocity (change in velocity), Δt = time interval

The car started from rest, meaning it had an initial velocity of 0 m/s. Its final velocity was 10 m/s. The time that it took for the car to go from 0 m/s to 10 m/s was 4.5 seconds.

  • a = (10 m/s - 0 m/s) / 4.50 s
  • a = 10/4.5
  • a = 2.222... m/s²

Now we have two known variables, mass and acceleration. We can solve for the force exerted on the car (and thus, the force the car exerts on the road) using the formula F = ma.

  • F = ma
  • F = (1200 kg)(2.222... m/s²)
  • F = 1200 · 2.222...
  • F = 2666.666667 N

The force that the car's tires exert on the road is 2667 N.

7 0
2 years ago
You kick a soccer ball with a speed of 31 m/s at an angle of 50 degrees. How long does it take the ball to reach the top of its
Harlamova29_29 [7]

Answer:

Reaches max height at t = 2.42s.

Explanation:

I've assumed we are neglecting air resistance. If not let me know and I'll update.

We want to examine the behaviour of the ball in the y-direction. In the absence of air resistance the only force acting on the ball is gravity, which produces an acceleration in the negative y direction.

3 0
3 years ago
Use the information below for the next five questions:
sergey [27]

Answer:  Please see answer in explanation column.

Explanation:

Given that

v≈(331 + 0.60T)m/s

where Temperature, T =  14°C

v≈(331 + 0.60 x 14)m/s

v =331+ 8.4 = 339.4m/s

In our solvings, note that

f= frequency

 λ=wavelength

L = length

v= speed of sound

a) Length of the pipe is calculated using the fundamental frequency formulae that

f=v/2L

Length = v/ 2f

= 339.4m/s/ 2 x 494Hz ( s^-1)= 0.3435m

b) wavelength of the fundamental standing wave in the pipe

L = nλ/2,

λ = 2L/ n

λ( wavelength )= 2 x 0.3435/ 1

= 0.687m

c) frequency of the fundamental standing wave in the pipe

F = v/  λ

= 339.4m/s/0.687m=

494.03s^-1 = 494 Hz

d) the frequency in the traveling sound wave produced in the outside air.

This is the same as the frequency in the open organ pipe = 494Hz

e)The wavelength of the travelling sound wave produced in the outside air is the same as the wavelength calculated in b above = 0.687m

f) To play D above middle c . the distance is given by

L =v/ 2 f

= 343/ 2 x 294

=0.583m

7 0
3 years ago
Which type of energy do you always have at the top of the first hill on a roller coaster?​
Verdich [7]

Answer:

Potential Energy

8 0
3 years ago
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Which of the following statements about ycarrier(x,t) is correct?
finlep [7]

Answer: Option D : is traveling rapidly but oscillating slowly.

Explanation:

ycarrier(x,t) is traveling rapidly but oscillating slowly.

8 0
3 years ago
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