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Masja [62]
3 years ago
8

Anthony is deciding between different savings accounts at his bank. He has four options, based on how frequently interest compou

nds. Which should he choose if he wants the best rate of return on his interest?
Physics
1 answer:
77julia77 [94]3 years ago
5 0
So annual compounding means that the account is compound once a year, semi-annual is 2 times a year, monthly compounded is every month (so 12 times a year). and daily is every day (so 365 times a year). If he wants the best rate of return on his interest, or the most money, he should choose daily compounding because his funds are being compounded every day. 
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Whats the answer for the second question ???
Rama09 [41]
We don't know the question you're talking about, hun.
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6 0
3 years ago
UV radiaGon having a wavelength of 120 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum kine
Solnce55 [7]

Answer:

K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J

Explanation:

First we calculate the energy of photon:

E = hc/λ

where,

E = Energy of Photon = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 120 nm = 1.2 x 10⁻⁷ m

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(1.2 x 10⁻⁷ m)

E = (16.565 x 10⁻¹⁹ J)(1 eV/1.6 x 10⁻¹⁹ J)

E = 10.35 eV

Now, from Einstein's Photoelectric equation we know that:

Energy of Photon = Work Function + K.E of Electron

10.35 eV = 4.82 eV + K.E

K.E = 10.35 eV - 4.82 eV

<u>K.E = 5.53 eV = 8.85 x 10⁻¹⁹ J</u>

4 0
3 years ago
Determine the mass of an object if it's moving at 5 m/s and has a momentum of 50 kg*m/s
Ganezh [65]
I think the mass is 250 kg
8 0
3 years ago
A rope of negligible mass is wrapped around a 225-kg solid cylinder of radius 0.400 m. the cylinder is suspended several meters
emmainna [20.7K]
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5 0
3 years ago
Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod
aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force=\frac{Gm_{1}m_{2} }{r^{2}}

Coulombs's Law= \frac{Kq_{1}q_{2} }{r^{2}}

6 0
4 years ago
Read 2 more answers
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