3 years ago

A child is thrown horizontally from a 45m tall tower with a velocity of 7m/s.

Physics

1 answer:

lesya692 [45]3 years ago

7 0

The child is thrown for 7 seconds

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3.14946 rad/s

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$I_i$ = Intial moment of inertia

$I_f$ = Final moment of inertia

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In this system the angular momentum is conserved

$L_i=L_f\\\Rightarrow I_i\omega_i=I_f\omega_f\\\Rightarrow \omega_i=\dfrac{I_f\omega_f}{I_i}\\\Rightarrow \omega_i=\dfrac{1\times \dfrac{2}{1.33}\times 2\pi}{3}\\\Rightarrow \omega_i=3.14946\ rad/s$

The angular velocity when the diver left the board is 3.14946 rad/s

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