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3 years ago

What is the potential energy of a 2kg potted plant that is on a 2 meter high plant stand?

1 answer:

5 0

Potential energy relative to the floor =

 (mass) x (gravity) x (height off the floor) =

 (2kg) x (9.8 m/s²) x (2m) =

 39.2 kg-m²/sec² = 39.2 joules 

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A roller coaster, traveling with an initial speed of 21 m/s, decelerates uniformly at -3.5

liberstina [14]

Answer:

S = Vo t + 1/2 a t^2 distance traveled

t = (V2 - V1) / a = (0 - 21) / -3.5 = 6 sec time to stop

S = 21 * 6 - 3.5 * 6^2 / 2 = 63 m distance traveled

3 0

1 year ago

Protons have electrical charge; electrons have. electrical charge

tekilochka [14]

Answer:

true

Explanation:

they both have an electrical charge

protons have a positive charge while electrons have a negative charge but both still have an electrical charge

6 0

3 years ago

For an object to be in static equilibrium, the net force must be equal to zero and and The center of gravity must be above the s

iren [92.7K]

Answer:

The normal force must equal the weight.

8 0

4 years ago

WOULUJUTUL RECIPECUIUS.

3241004551 [841]

The force between the two objects is 19.73 nN.

Explanation:

Any force acting between two objects tends to be directly proportional to the product of their masses and inversely proportional to the square of the distance between the two objects. And this kind of attraction force between two objects is termed as gravitational force.

So if we consider $M_{1}$ and $M_{2}$ as the masses of both objects and let d be the distance of separation of two objects. Then the force between the two objects can be determined as below:

$\text {Gravitational force}=\frac{G \times M_{1} \times M_{2}}{d^{2}}$

As gravitational constant $G=6.67 \times 10^{-11} \mathrm{m}^{3} \mathrm{kg}^{-1} \mathrm{s}^{-2}$ , $M_{1}$ = 20 kg and $M_{2}$ = 100 kg, while d = 2.6 m, then

$\text {Gravitational force}=\frac{6.67 \times 10^{-11} \times 20 \times 100}{(2.6)^{2}}=\frac{6.67 \times 20 \times 10^{-9}}{6.76}$

Thus, we get finally,

$\text {Gravitational force}=19.73 \times 10^{-9} \mathrm{N}$

As we know, nano denoted by letter 'n' equals to $10^{-9}$

So the force acting between two objects is 19.73 nN.

7 0

3 years ago

After a massive-star supernova, what is left behind?.

scoray [572]

Answer: A Nebula is left behind. A spectacular explosion in which a star ejects most of its mass in a violently expanding cloud of debris.

Hope this helps!

8 0

3 years ago