Answer:
I think you just have to input the horizontal velocity component.
Explanation:
Assuming no air resistance
The horizontal velocity is constant at
vx = 17.5cos71 = 5.6974... = 5.70 i m/s
The vertical velocity varies with gravity
vy = 17.5sin71 + -9.81(22) = -199.273... = -199 j m/s
v = 5.70i - 199j m/s
arguably one should round to only two significant digits
<span>A. A girl hits a volleyball. Her hand exerts a force on the ball, and the ball exerts a force on her han</span>
Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
u = 0 m/s
g = 9.8 m/s²
s = 0 + 0.5 × 9.8 × 2.2²
s = 23.72 m
b) impact velocity
v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
v = 21.56 m/s²
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