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amm1812
3 years ago
10

How long does it take a car to go 1000 m if it is going at 50 m/sec?

Physics
1 answer:
Lina20 [59]3 years ago
3 0

The car would take 20 seconds to go 1000 meters. This can be found by dividing 1000 by 50.

If you need more help, comment below and I will be happy to assist.

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2. Radio stations are usually identified by their
Mice21 [21]

The wavelength of the radio wave is 0.303 m.

<h3>Wavelength</h3>

The wavelength of the wave is the distance traveled by the wave.

c = fλ

where;

  • c is speed of light = 3 x 10⁷ m/s
  • f is frequency
  • λ is wavelength

λ = c/f

λ = (3 x 10⁷ ) / (99 x 10⁶)

λ = 0.303 m

Thus, the wavelength of the radio wave is 0.303 m.

Learn more about wavelength here: brainly.com/question/10728818

3 0
2 years ago
A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from t
marishachu [46]

Answer:

The impact occured at a distance of 2478.585 meters from the person.

Explanation:

(After some research on web, we conclude that problem is not incomplete) The element "Part A" may lead to the false idea that question is incomplete. Correct form is presented below:

<em>A person, with his ear to the ground, sees a huge stone strike the concrete pavement. A moment later two sounds are heard from the impact: one travels in the air and the other in the concrete, and they are 6.4 seconds apart. How far away did the impact occur? (Sound speed in the air: 343 meters per second, sound speed in concrete: 3000 meters per second)</em>

Sound is a manifestation of mechanical waves, which needs a medium to propagate themselves. Depending on the material, sound will take more or less time to travel a given distance. From statement, we know this time difference between air and concrete (\Delta t), in seconds:

\Delta t = t_{A}-t_{C} (1)

Where:

t_{C} - Time spent by the sound in concrete, in seconds.

t_{A} - Time spent by the sound in the air, in seconds.

By suposing that sound travels the same distance and at constant speed in both materials, we have the following expression:

\Delta t = \frac{x}{v_{A}}-\frac{x}{v_{C}}

\Delta t = x\cdot \left(\frac{1}{v_{A}}-\frac{1}{v_{C}}  \right)

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  } (2)

Where:

v_{C} - Speed of the sound in concrete, in meters per second.

v_{A} - Speed of the sound in the air, in meters per second.

x - Distance traveled by the sound, in meters.

If we know that \Delta t = 6.4\,s, v_{C} = 3000\,\frac{m}{s} and v_{A} = 343\,\frac{m}{s}, then the distance travelled by the sound is:

x = \frac{\Delta t}{\frac{1}{v_{A}}-\frac{1}{v_{C}}  }

x = 2478.585\,m

The impact occured at a distance of 2478.585 meters from the person.

7 0
3 years ago
Photosynthesis transforms into chemical energy by from food sugars, Cellular respiration releases the by sugars.​
Anarel [89]

Answer:

a

Explanation:

poop

5 0
3 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2060 × 103 seconds (about
Fittoniya [83]

Answer:

Acceleration, a=2.22\times 10^{-3}\ m/s^2

Explanation:

It is given that,

Time period of revolution of the moon, T=2060\times 10^3\ s

If the distance from the center of the moon to the surface of the planet is, h=235\times 10^6\ m

The radius of the planet, r=3.9\times 10^6\ m

Let a is the moon's radial acceleration. Mathematically, it is given by :

a=R\times \omega^2, R is the radius of orbit

Since, \omega=\dfrac{2\pi}{T}

The radius of orbit is,

R=r+h

R=3.9\times 10^6\ m+235\times 10^6\ m=238900000\ m

So, a=\dfrac{4\pi^2 R}{T^2}

a=\dfrac{4\pi^2 \times 238900000}{(2060\times 10^3)^2}

a=2.22\times 10^{-3}\ m/s^2

Hence, this is the required solution for the radial acceleration of the moon.

5 0
3 years ago
Four wrestlers step on a scale for a tournament. Wrestler A weighs in at 170 pounds; wrestler B weighs in at 168 pounds; wrestle
OLga [1]
The force due to gravity is equal to the product of the mass and acceleration due to gravity. Since the acceleration due to gravity is constant, we just have to rely on the comparison of their masses to determine the mass effect. Thus, the answer to this item is Wrestler C weighing 171 pounds. 
7 0
4 years ago
Read 2 more answers
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