Answer:
An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground.
Explanation:
hope this helps
The mass is rising with a constant speed.
=> So it has no vertical acceleration.
=> So there is no net vertical force acting on it.
=> So the sum of the vertical forces on it is zero.
There are two vertical forces acting on the mass.
=> the force of gravity, pulling it down
=> the tension in the cable, pulling it up.
The force of gravity acting on the mass (its weight) is (mass) x (gravity).
=> That's (120 kg) x (9.8 m/s²) downward.
=> That's 1,176 newtons downward.
If the vertical forces add up to zero, the other force ... the tension in the cable ... must be the same magnitude in the opposite direction.
=> The force of tension in the cable is <em>1,176 newtons upward</em>.
The answer is A) because knowing Net force is equal too mass * acceleration, we can sub in what is given, the net force here would be 5N so the equation the looks like 5N=10kg*a and then dividing out 10kg we are then left with .5 m/s^2
Explanation:
According to Newton's first law of motion Force is the external energy that changes or tends the state of rest or of uniform motion of body in straight line .
hope it is helpful to you ☺️
Answer:
0.80 m
Explanation:
Neglecting friction, the total mechanical energy of the pendulum is constant.
E = K + U where K = kinetic energy and U = potential energy.
At its release point of 0.80 m, the pendulum bob has a mechanical energy which is equal to its potential energy, since, its initial kinetic energy is zero. By the time the bob swings to the other end, it has a mechanical energy equal to it initial potential energy since total energy is conserved.
Neglecting friction, the pendulum bob would swing back to its original height of 0.80 m since the total mechanical energy is conserved and at its highest point, it is purely potential energy.
So, the height the pendulum bob swings to after release from a height of 0.80 m neglecting fiction is 0.80 m.