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2 years ago

Reading the temperature of a solution by using a thermometer is an example of a(n) ________.

Physics

1 answer:

blsea [12.9K]2 years ago

4 0

Answer:

B. Observation

Explanation:

Using a thermometer to read the temperature of a solution is tantamount to the making an observation.

Observation are recorded using our senses of sight, taste, earing, feeling etc or by the use of instrument.

Through observation, data is usually collected to make inferences about an experiment.
An observation leads to the formulation of a hypothesis which is scientific guess that leads to experimental designs.
Conclusions are drawn from the information of data obtained from an experiment.

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In an RC circuit, what fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for

4vir4ik [10]

Answer:

The fraction fraction of the final energy is stored in an initially uncharged capacitor after it has been charging for 3.0 time constants is

$k = 0.903$

Explanation:

From the question we are told that

The time constant $\tau = 3$

The potential across the capacitor can be mathematically represented as

$V = V_o (1 - e^{- \tau})$

Where $V_o$ is the voltage of the capacitor when it is fully charged

So at $\tau = 3$

$V = V_o (1 - e^{- 3})$

$V = 0.950213 V_o$

Generally energy stored in a capacitor is mathematically represented as

$E = \frac{1}{2 } * C * V ^2$

In this equation the energy stored is directly proportional to the the square of the potential across the capacitor

Now since capacitance is constant at $\tau = 3$

The energy stored can be evaluated at as

$V^2 = (0.950213 V_o )^2$

$V^2 = 0.903 V_o ^2$

Hence the fraction of the energy stored in an initially uncharged capacitor is

$k = 0.903$

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3 years ago

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Kitty [74]

Answer:you in connections too?

Explanation:

7 0

3 years ago

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Two charges, each q, are separated by a distance r, and exert mutual attractive forces of F on each other. If both charges becom

jeka57 [31]

Answer:

F = ⅔ F₀

Explanation:

For this exercise we use Coulomb's law

F = k q₁q₂ / r²

let's use the subscript "o" for the initial conditions

F₀ = k q² / r²

now the charge changes q₁ = q₂ = 2q and the new distance is r = 3 r

we substitute

F = k 4q² / 9 r²

F = k q² r² 4/9

F = ⅔ F₀

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3 years ago

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sweet-ann [11.9K]

Answer:

50 Mph.

Explanation:

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2 years ago

Which of the following is an example of a force inertia push pull

Whitepunk [10]

A force can be considered a push or pull

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3 years ago