<h2>
Its velocity when it crosses the finish line is 119.40 m/s</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = ?
Time, t = 6.70 s
Displacement, s = 1/4 mi = 0.25 mi = 400 m
Substituting
s = ut + 0.5 at²
400 = 0 x 6.70 + 0.5 x a x 6.70²
a = 17.82 m/s²
Now we have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = ?
Time, t = 6.7 s
Acceleration, a = 17.82 m/s²
Substituting
v = u + at
v = 0 + 17.82 x 6.7
v = 119.40 m/s
Its velocity when it crosses the finish line is 119.40 m/s
Answer:
(a) Angular acceleration is 1.112 rad/s².
(b) Average angular velocity is 2.78 rad/s .
Explanation:
The equation of motion in Rotational kinematics is:
θ = θ₀ + 0.5αt²
Here θ is angular displacement at time t, θ₀ is angular displacement at time t=0, t is time and α is constant angular acceleration.
(a) According to the problem, θ is 13.9 rad, θ₀ is zero as it is at rest and t is 5 s. Put these values in the above equation:
13.9 = 0 + 0.5α(5)²
α = 1.112 rad/s²
(b) The equation of average angular velocity is:
ω = Δθ/Δt
ω = 
ω = 2.78 rad/s
Answer:
The oxidation number of a monatomic (composed of one atom) ion is the same as the charge of the ion. For example, the oxidation numbers of K+, Se2−, and Au3+ are +1, -2, and +3, respectively. The oxidation number of oxygen in most compounds is −2.
Explanation:
Answer
given,
Radius of sphere = 6.38 × 10⁶ m
time = 1 day = 86400 s



a) at equator


v = 464 m/s
acceleration of the person



b) at a latitude of 61.0 ° north of the equator.






acceleration of the person



That is a paradox b/c stationary means not moving