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Vesna [10]
2 years ago
14

When a certain string is clamped at both ends, the lowest four resonant frequencies are 50, 100, 150, and 200 Hz. When the strin

g is also clamped at its midpoint, the lowest four resonant frequencies are __________.
Physics
1 answer:
mario62 [17]2 years ago
4 0

Answer:

Explanation:

Given

Lowest four resonance frequencies are given with magnitude

50,100,150 and 200 Hz

The frequency of vibrating string is given by

f=\frac{n}{2L}\sqrt{\frac{T}{\mu }}

where n=1,2,3 or ...n

L=Length of string

T=Tension

\mu =Mass per unit length

When string is clamped at mid-point

Effecting length becomes L'=0.5 L

Thus new Frequency becomes

f' =\frac{n}{L}\sqrt{\frac{T}{\mu }}

i.e. New frequency is double of old

so new lowest four resonant frequencies are 100,200,300 and 400 Hz      

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Answer:(4).

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1 year ago
A car accelerates at a rate of 13m/s^2[S]. If the car's initial velocity is 120km/h[N]. What will be its final velocity in m/s,
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Answer:

the final velocity of the car is 59.33 m/s [N]

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IMPORTANT 3 QUESTIONS!
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Answer:

7. 20,000,000 mL.

8. 8,000 m.

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First, we shall convert from mile to kilometre.

This can be done as follow:

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Finally, we shall convert 8 km to metre (m).

This is illustrated below:

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This is illustrated below:

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