Magnetic Energy density affected by area?

A river flows due south with a speed of 2.0 m/s .You steer a motorboat across the river; your velocity relative to the water is

mihalych1998 [28]

Answer:

a) $v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

b) $\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

c) $t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

d) $Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

Explanation:

Part a

For this case the figure attached shows the illustration for the problem.

We know that $v_y = 2 m/s$ represent the velocity of the river to the south.

We have the velocity of the motorboard relative to the water and on this case is $V_x= 4.8 m/s$

And we want to find the velocity of the motord board relative to the Earth $v_m$

And we can find this velocity from the Pythagorean Theorem.

$v_m =\sqrt{v^2_x + v^2_y} = \sqrt{(2m/s)^2 +(4.8 m/s)^2}= 5.2 m/s$

Part b

We can find the direction with the following formula:

$\theta= tan^{-1} \frac{v_y}{v_x} = tan^{-1} (\frac{2}{4.8})= 22.62$ degrees and on this case to the South of the East.

Part c

For this case we can use the following definition

$D = Vt$

The distance would be D = w = 600 m and the velocity V = 4.8m/s and if we solve for t we got:

$t= \frac{w}{v_m}= \frac{600m}{4.8 m/s}= 125 s$

Part d

For this case we can use the same definition but now using the y compnent we have:

$Y = v_y t$

And replacing we got:

$Y = 2 m/s * 125 s = 250m$

So it would be 250 to the South

7 0

3 years ago

Two ladders of uniform density and equal mass m are propped up against

-BARSIC- [3]

Answer:

i need some more coins LMAI

7 0

4 years ago

Two rockets are fired at each other with initial velocities of 150m/s150m/s and are 6000m6000m apart. The first rocket is accele

Nataliya [291]

Answer:

3469.788 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

First rocket

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 5\times t^2\\\Rightarrow s=150t+2.5t^2\ m$

Second rocket

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=150\times t+\frac{1}{2}\times 15\times t^2\\\Rightarrow s=150t+7.5t^2\ m$

When this will collide the total distance they would have covered would be 6000 m.

$6000=150t+2.5t^2+150t+7.5t^2\\\Rightarrow 6000=300t+10t^2\\\Rightarrow 10t^2+300t-6000=0$

$t=5\left(\sqrt{33}-3\right),\:t=-5\left(3+\sqrt{33}\right)\\\Rightarrow t=13.72, -43.72$

Hence at 13.72 seconds they will collide assuming they are launched at the same time.

$s=150t+7.5t^2\\\Rightarrow s=150\times 13.72+7.5\times 13.72^2\\\Rightarrow s=3469.788\ m$

The second rocket would have gone 3469.788 m when they collide

7 0

4 years ago

Read the following story and tell me how Harper used the FITT principle. Harper works out 4-5 days a week for 60 minutes a day.

sweet [91]

Harper used the the frequency principle (F) by planning to work out 4-5 days a week. Frequency is how often you exercise, usually on a weekly basis.

She used the intensity principle (I) by deciding to exercise on a moderate level, rather than, for example, an intense workout. Intensity is basically how hard you exercise and push yourself.

She then used the time (T) principle by choosing to workout for 60 mins per day. Time meaning how much time you spend working out each day.

And lastly, she used the type (T) principle by devising a specific type and/or set of exercise(s) to do, which in her case, is drills, jogging, and weight lifting.

So all in all, Harpers frequency is 4-5 days per week, her intensity is moderate, her time is 60 mins/day, and type is basketball drills, jogging and weight lifting.

Hope I helped! :)

7 0

3 years ago

a steam engine works on its vicinity and 285k heat is released with the help of 225C energy absorbed to the system. what is the

Sedaia [141]

Explanation:

define the term specific heat capacity of water

7 0

3 years ago

Magnetic Energy density affected by area?​

Magnetic Energy density affected by area?