Answer:
v = 30.39 m/s
Explanation:
given,
mass of glider,M = 680 Kg
mass of the skydiver, m = 68 Kg
horizontal velocity,V = 30 m/s
when skydiver releases, velocity,v = 30 m/s
velocity if the glider,v' = ?
use the conservation of momentum
M V = m' v' + m v
m' = 680-68 = 612 Kg
680 x 30 = 612 x v + 60 x 30
612 v = 18600
v = 30.39 m/s
since the skydiver's speed will be the same as before release
The glider should continue to travel at 30.39 m/s since there are no external forces acting on it
E = q/r^2
where r is perpendicular distance between the point and source charge
Ex = E cos theta
Ey = E sin theta
take theta angle between horizontal and line joining the point charge and the point
By definition, the wavelength of an electromagnetic wave is calculated using the following formula:
Where:
\lambda = wavelength
c = speed of light =
f = frequency of the wave.
This relation means that the division of the wavelength λ between the frequency f is always equal to the speed of light.
Thus:
the velocity v of this wave must be equal to c.
Finally the correct answer is D.
First solve the potential energy of the biker. using the fomula:
PE = mgh
where m is the mass of the object
g is the acceleration due to gravity ( 9.81 m/s2)
h is the height
PE = 96 kg ( 1120 m ) ( 9.81 m/s2)
PE = 1054771.2 J
then power = Work / time
P = 1054771.2 J / ( 120 min ) ( 60 s / 1 min)
P = 146.5 W