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2 answers:
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Answer:
x=1 and x=0
Step-by-step explanation:
We need to find the points at which the graphs y = x^2 + x – 2 and y = 2x – 2 intercept.
We know that:
x^2 + x – 2 = 2x – 2
x^2 - x = 0
Factorizing:
x(x-1) = 0
Therefore, the solution to the system of equation is x=1 and x=0.
Answer:
Step-by-step explanation:
Given that,
Vector n = 4i-j
Vector m = 3i+3j
We need to find the value of m+2n.
Put all the values,
m+2n = (3i+3j)+2(4i-j)
= (3i+3j)+8i-2j
=11i+j
Magnitude of vector,
So the correct option is (c).