When you divide by a fraction, flip the fraction over and change divide to multiply:
3/2 / 1/8 would become:
3/2 x 8/1
8/1 simplifies to 8
You get:
3/2 x 8 = 12
The answer is:
Three-halves times 8 = 12
Answer:
0
Step-by-step explanation:
given that we roll a fair die repeatedly until we see the number four appear and then we stop.
the number 4 can appear either in I throw, or II throw or .... indefinitely
So X = the no of throws can be from 1 to infinity
This is a discrete distribution countable.
Sample space= {1,2,.....}
b) Prob ( 4 never appears) = Prob (any other number appears in all throws)
= 
where n is the number of throws
As n tends to infinity, this becomes 0 because 5/6 is less than 1.
Hence this probability is approximately 0
Or definitely 4 will appear atleast once.
Answer:
Step-by-step explanation:
We are looking for two numbers,
and
. From the problem statement, we can setup the following equation:





Because 3 is the only integer solution, the answer is 3 and 4.