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Mariulka [41]
3 years ago
10

The angular momentum of a system remains constant when: A. the total kinetic energy is constant

Physics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

D. when no torque acts on the system

Explanation:

The angular momentum of a system is defined as:

L=I\omega

where

I is the moment of inertia of the system

\omega is the angular velocity

This is the equivalent of the linear momentum, p, for rotational motion

p=mv

where m is the mass of the system and v is its velocity. From Newton' laws, we know that the change in linear momentum is equal to net force acting on the system, F:

F=\frac{\Delta p}{\Delta t}

The analogous relationship for a rotational motion is:

\tau=\frac{\Delta L}{\Delta t}

where \tau is the net torque acting on the system. This is the law of conservation of angular momentum, which states that the rate of change of the angular momentum of an object is equal to the net torque on the system: therefore, when no torque acts on the system, the angular momentum is conserved.

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The correct answer is - Denying the pleasure of an immediate reward so that you can receive a greater reward later.

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What happens to energy and matter when a wave moves through space?
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4 0
3 years ago
A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the building.
Nadusha1986 [10]

The height of the building is 53.4 m (projectile motion)

Explanation:

The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:

d=v_x t  

where:

v_x = 50 m/s is the horizontal velocity of the ball, which is constant since there are no forces in this direction

d = 165 m is the horizontal distance travelled by the ball

Solving for t, we find the time of flight:

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation

s=ut+\frac{1}{2}at^2  

where  

s is the vertical displacement, which is the height of the building

u = 0 is the initial vertical velocity of the ball

t = 3.3 s is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity  

Solving for s, we find the height of the building:

s=0+\frac{1}{2}(9.8)(3.3)^2=53.4 m

Learn more about projectile motion here:

brainly.com/question/8751410

#LearnwithBrainly

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4 years ago
What is the kinetic energy when the pendulum is at the halfway point
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The answer is 0 , hope this helps
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3 years ago
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