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Taya2010 [7]
3 years ago
15

HELP ME PLEASE!!!!!! A couch is pushed with a force of 79 N and moves a distance of 7 m across the floor. How much work was done

in moving the couch?
Physics
1 answer:
Korolek [52]3 years ago
3 0
Work is the applied force (79n) x distance (7m)

So the answer is 553 joules
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A frequency generator sends a 550Hz sound wave through both water and ice. What is the difference in wavelength between the wave
LUCKY_DIMON [66]

Answer:

3.1

Explanation:

use formula f = v/lambda

7 0
3 years ago
A piston-cylinder device initially contains 0.08 m3 of nitrogen gas at 150 kPa and 200°C. The nitrogen is now expanded to a pres
Lemur [1.5K]

Answer:

V_2 = 0.125 m^3

Work done =  = 5 kJ

Explanation:

Given data:

volume of nitrogen v_1 = 0.08 m^3

P_1 = 150 kPa

T_1 = 200 degree celcius = 473 Kelvin

P_2 = 80 kPa

Polytropic exponent n = 1.4

\frac{T_2}{T_1} = [\frac{P_2}{P_1}]^{\frac{n-1}{n}

putting all value

\frac{T_2}{473} = [\frac{80}{150}]^{\frac{1.4-1}{1.4}

\frac{T_2} = 395.23 K = 122.08 DEGREE \ CELCIUS

polytropic process is given as

P_1 V_1^n = P_2 V_2^n

150\times 0.08^{1.4} = 80 \times V_2^{1.4}

V_2 = 0.125 m^3

work done = \frac{P_1 V_1 -P_2 V_2}{n-1}

= \frac{150 \times 0.8 - 80 \times 0.125}{1.4-1}

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4 0
3 years ago
A particle cannot generally be localized to distances much smaller than its de Broglie wavelength. This fact can be taken to mea
Vlada [557]

The De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°

<h3>How is the De broglie wavelength of a thermal neutron at room temperature calculated?</h3>

Temperature, T = 300K

Momentum, p = mv

Therefore v = p/m

Energy, E= 1/2 m( p/m) ²

Boltzman Energy= 3/2 KT

3/2KT = 1/2 m(p/m)²

Therefore p =  \sqrt{3RTm}

According to De broglie hypothesis, P = h ÷ λ

Therefore,    λ  = h ÷ \sqrt{3RTm}

                     = 6.6× 10^{-34} ÷  \sqrt{3 \times 1.38 \times  10^{-23}  \times 300 \times 1.6 \times  10^{-27} }

                     = 0.15 × 10^{-9}

Therefore the De broglie wavelength of a thermal neutron at room temperature 300K = 1.5 × A°

To learn more about De broglie wavelength, refer: <u>https://brainly.in/question/6131028</u>

#SPJ4

6 0
2 years ago
6300 divided by 32.8
Ilya [14]
<h2>6300÷32.8</h2><h3>=192.07317073</h3>

<h2>6300÷33</h2><h3>=190.90909091</h3>

please mark this answer as brainlist

7 0
3 years ago
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The role of learning in motivation is most obvious from the influence of<br><br>​
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A thing that motivates or encourages one to do something is an incentive. Answer: Incentives.

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