<span>The chemical formula of Helium is He.
Question 1 :
Given n = 1.11 x 10^-6
To get no. of the particle,
No of particle = no. of mole x Avogadro Constant
p = n x NA
1 mol of Helium = 6.02 x 10^23
No of atoms = (6.02 x 10^23) x (1.11 x 10^-6)
= 6.66 x 10^17
................................
Question 2 :
Given p = 4.29x10^21
p = n x NA
4.29 x 10^21 = n x (6.02 x 10^23)
(4.29 x 10^21) / (6.02 x 10^23) = n
n = Approximately 7.126 x 10^-3
Hope the answer is right :)</span>
The number of mole of copper in the sample is 0.008 mole.
Mole is simply defined as the unit of amount in a substance.
The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e
Mole = mass / molar mass
With the above information, we can obtain the mole of copper in the compound as follow:
Mass of copper = 0.5066 g
Molar mass of copper = 63.5 g/mol
<h3>Mole of copper =? </h3>
Mole = mass / molar mass
Mole of copper = 0.5066 / 63.5
<h3>Mole of copper = 0.008 mole </h3>
Therefore, 0.008 mole of copper was initially present in the compound.
Learn more: brainly.com/question/14295066
<u>Answer:</u> The temperature of the ideal gas is 
<u>Explanation:</u>
To calculate the temperature, we use the equation given by ideal gas equation:
where,
P = Pressure of the gas = 142,868 Pa = 142.868 kPa (Conversion factor: 1 kPa = 1000 Pa)
V = Volume of gas = 1.0000 L
n = number of moles of ideal gas = 0.0625 moles
R = Gas constant = 
T = temperature of the gas = ?
Putting values in above equation, we get:
Hence, the temperature of the ideal gas is
"<span>b. God had created a mechanistic universe that could only be understood through the Bible" is the best option since Deists believe God treats the universe in a "hands off" way. </span>
Answer:
222.30 L
Explanation:
We'll begin by calculating the number of mole in 100 g of ammonia (NH₃). This can be obtained as follow:
Mass of NH₃ = 100 g
Molar mass of NH₃ = 14 + (3×1)
= 14 + 3
= 17 g/mol
Mole of NH₃ =?
Mole = mass /molar mass
Mole of NH₃ = 100 / 17
Mole of NH₃ = 5.88 moles
Next, we shall determine the number of mole of Hydrogen needed to produce 5.88 moles of NH₃. This can be obtained as follow:
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
3 moles of H₂ reacted to produce 2 moles NH₃.
Therefore, Xmol of H₂ is required to p 5.88 moles of NH₃ i.e
Xmol of H₂ = (3 × 5.88)/2
Xmol of H₂ = 8.82 moles
Finally, we shall determine the volume (in litre) of Hydrogen needed to produce 100 g (i.e 5.88 moles) of NH₃. This can be obtained as follow:
Pressure (P) = 95 KPa
Temperature (T) = 15 °C = 15 + 273 = 288 K
Number of mole of H₂ (n) = 8.82 moles
Gas constant (R) = 8.314 KPa.L/Kmol
Volume (V) =?
PV = nRT
95 × V = 8.82 × 8.314 × 288
95 × V = 21118.89024
Divide both side by 95
V = 21118.89024 / 95
V = 222.30 L
Thus the volume of Hydrogen needed for the reaction is 222.30 L
