Answer:
200 grams of NaOH are produced with the reaction of 5.00 moles of water
Explanation:
First of all you apply a rule of three to know the amount of moles of NaOH as follows: if 2 moles of water produce 2 moles of NaOH, 5 moles of water how many moles would they produce?

moles of NaOH= 5
Being:
- Na: 23 g/mole
- O: 16 g/mole
- H: 1 g/mole
the molar mass of NaOH is: 23 g/mole + 16 g/mole + 1 g/mole= 40 g/mole
Then a rule of three applies as follows: if in 1 mole there are 40 g of NaOH, in 5 moles how much mass is there?

mass= 200 g
<u><em>200 grams of NaOH are produced with the reaction of 5.00 moles of water</em></u>
Density = Mass of Object / Volume of water displaced.
The volume of water displaced is the same as the volume of the object.
Density = 118 g / 25 ml
= 4.72 g/ml
But 1 liter = 1000 cm³
1 mL = 1 cm³
Density = 4.72 g/ml = 4.72 g/cm³